Answer:
Step-by-step explanation:
Let S be the sample space of an experiment and E is an event associated with the experiment.
Let n(S) and n(E) denote the number of element in S and E.
P(E) is the probability of an event E
The number of elements on the sample space ;
n(S) = n(r) + n(b) + n(g) = 10 + 20 + 30 = 60
Hence, the event of drawing 5chips from the box n(S) = C(60,5)
A) probability of drawing 5chips from the box which are all blue ;
P(E) = n(E) / n(S) = 20C5 x 40C0 / 60C5 = 0.0028
by combination method ; nCr = n!/r!(n - r)!
B) the probability of drawing the indicated chips at least 1 green ;
Application of the binomial formula comes in ; nCr x p^r x q^n-r
= P(E) = 1 - p(x <1) = 1 - po = 1 - 30C0 x 30C5 / 60C5
= 0.9739
C) the probability of drawing the indicated chips at most 1 red;
P(E) = p(no red) + p(one red)
= 10C0 x 50C5 + 10C1 x 50C4 / 60C5
= 0.8096
