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Paha777 [63]
3 years ago
9

Which is a true statement about an isosceles right triangle? A.The hypotenuse is square root 3 times as long as either leg. B. T

he hypotenuse is square root 2 times as long as either leg. C. Each leg is square root 2 times as long as the hypotenuse. D. Each leg is square root 3 times as long as the hypotenuse.
Mathematics
2 answers:
Alborosie3 years ago
7 0

Answer:

B. The hypotenuse is square root 2 times as long as either leg.

Step-by-step explanation:

The answer is B.

Let's use Pythagoras to prove it.

h^2=a^2+b^2

In this case since its an isoceles right triangle, a and b most be the same.

Let's say that the measure of the sides that are equal is x and the hypotenuse is h.

Pythagoras tells us the following:

h^2=x^2+x^2

Solving for h:

h=\sqrt{x^2+x^2} =\sqrt{2x^2}=x\sqrt{2}

The hypotenuse is square root 2 times as long as the sides, in this case x wich could be any number.

qwelly [4]3 years ago
4 0
An isosceles right triangle is a special right triangle where the legs are represented by x and the hypotenuse by x*the square root of 2 so your answer is B.
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Substitute (–5, 0.5) into x – 4y = –7 to get .
lesya [120]

Answer:

-7

Step-by-step explanation:

Coordinates are listed as (x,y) so x = -5 and y = .5

If you substitute the numbers in place of the letters, you get:

(-5) - 4(.5) = -7

-5 - 2 = -7

-7 = -7

Marking as Brainliest is much appreciated.

8 0
4 years ago
Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea
creativ13 [48]
Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

\begin{tabular}
{|c|c|c|c|c|c|c|c|c|}
1229&1292&1187&1257&1268&1316&1275& 1317&1275
\end{tabular}

Part A:

The sample mean is given by:

\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\  \\  = \frac{11416}{9} =1268

Therefore, the sample mean is 1268.



Part B:

We calculate the sample standard deviation as follows:

s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15



Part C:

The 90% confidence interval is given by:

90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\  \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\  \\ =(1268-5, \ 1268+5)=(1263, \ 1273)
8 0
3 years ago
Increase by 40% (write the decimal multuplier)​
DanielleElmas [232]

Answer: 0.040

Step-by-step explanation:

6 0
3 years ago
What the answer question
kobusy [5.1K]

Answer:

             \bold{A_{_{\Delta XYZ}}=927.5\ cm^2}

Step-by-step explanation:

m∠Z = 180° - 118° - 28° = 34°

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\dfrac{\overline{XY}}{\sin Z}=\dfrac{\overline{YZ}}{\sin X}\\\\\\\overline{XY}=\dfrac{\overline{YZ}}{\sin X}\cdot\sin Z\\\\\\\overline{XY}=\dfrac{42}{0.4695}\cdot0.5592\\\\\overline{XZ}=50.024281...\\\\\\A_{_{\Delta XYZ}}=\frac12\cdot\overline{XY}\cdot\overline{YZ}\cdot\sin(\angle Z)\\\\\\A_{_{\Delta XYZ}}\approx\frac12\cdot50.0243\cdot42\cdot0.8829=927.4955...\approx927.5

8 0
3 years ago
At a certain college, the ratio of men to women is 6 to 5. If there are 1,500 men, how many women are there?
Fed [463]

Let 6x represent the men

5x represents the women

The ratio of men to women is 6 to 5 or 6/5


6x / 5x = 1500/ W  where W is the number of women

6/5 = 1500/W

W =  1250 women


4 0
4 years ago
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