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3 years ago

2/3 (x + 7) = 10 A) 22 B) 8 C)- 1 3 D 41 3 help me quick plz

Mathematics

1 answer:

otez555 [7]3 years ago

4 0

Answer:

Step-by-step explanation:

D BECAUSE IT IS D

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3) What is an equation for the line that passes through the coordinates (-1.2) and (7,6) ?

OLEGan [10]

Answer:

$y=\frac{1}{2} x+\frac{5}{2}$

Step-by-step explanation:

First find the slope using the slope using the given points. Remember that the slope is the change in y over the change in x.

$\frac{6-2}{7- (-1)}=\frac{4}{8}=\frac{1}{2}$

So now we have the equation $y=\frac{1}{2} x+b$ , and we need to find out what b is. We can do this by pointing a point (either one, but I'll use -1,2) into the equation

$2=\frac{1}{2}(-1)+b$

Rearrange the equation so it equals b

$\frac{5}{2}=b$

Put it together and that's the final equation!

$y=\frac{1}{2} x+\frac{5}{2}$

7 0

3 years ago

Find the measure of line segment TU. Assume that lines which appear to be tangent to the circle are tangent.

Sedaia [141]

Given:

A figure of a circle. A secant SU and a tangent SR is drawn to the circle from the external point S.

To find:

The measure of the line segment TU.

Solution:

According to the secant tangent segment theorem, the square of tangent is equal to the product of secant and external segment of the secant.

Using secant tangent segment theorem, we get

$SR^2=SU\times ST$

$(40)^2=(32+2x-2)\times (32)$

$1600=(30+2x)(32)$

$1600=960+64x$

Subtract both sides by 960.

$1600-960=64x$

$640=64x$

Divide both sides by 64.

$\dfrac{640}{64}=x$

$10=x$

Now, the measure of the line segment TU is:

$TU=2x-2$

$TU=2(10)-2$

$TU=20-2$

$TU=18$

Therefore, the correct option is C.

6 0

3 years ago

If the length of one leg in this triangle is .find the length of the hypotenuse.

Sonja [21]

By Pythagorean theorem we find that the length of the hypotenuse is $r = \sqrt{2}\cdot l$ .

<h3>How to find the length of the hypotenuse</h3>

In the image attached we have a <em>right</em> triangle with two legs of <em>same</em> length. The hypotenuse of <em>right</em> triangles can be found by Pythagorean theorem, whose form is:

$r = \sqrt{l^{2}+l^{2}}$