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Alinara [238K]
3 years ago
11

 4x+2y≥24 in slope intercept form

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0
4x+2y ≥ 24
2y ≥ -4x +24
y ≥ -2x+12
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Which equals the product of (x – 3)(2x + 1)?
hram777 [196]

Answer:

2x^2 – 5x – 3

Step-by-step explanation:

<u>Apply FOIL method: </u>

=x*2x+x*1+(-3)*2x+(-3)*1

<u>Apply minus-plus rules:</u>

=2xx+1*x-3*2x-3*1

Simplify:

=2x^2 – 5x – 3

Your Answer Is 2x^2 – 5x – 3

plz mark me as brainliest :)

6 0
3 years ago
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James is making a paper chain from different colored paper strips. He joins the links in the following pattern: red, blue, red,
Whitepunk [10]

Answer:

red

Step-by-step explanation:

1-red

2-blue

3-red

4-blue

5-red

6-blue

7-red

8-blue

9-red

10-blue

11-red

12-blue

13-red

14-blue

15-red

16-blue

17-red

18-blue

19-red

20-blue

21-red

22-blue

23-red

im so smart fr

8 0
2 years ago
Write an equation perpendicular to x-4y=20 that passes through the point 2,-5
marshall27 [118]

Answer:

  4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

  4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

  4(2) +(-5) = constant = 3

The line of interest has equation ...

  4x + y = 3

3 0
3 years ago
Examine the following diagram:
Lisa [10]

Answer:

Its C: 41°

Step-by-step explanation:

it was right on edg :)

6 0
3 years ago
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Ignoring leap days, the days of the year can be numbered 1 to 365. Assume that birthdays are equally likely to fall on any day o
faust18 [17]

Answer:

Follows are the solution to the given question:

Step-by-step explanation:

They can count the days of the year 1 to 365. The random project consists of drawing a sample of n objects from D where elements are n people's birth in a group but instead, D = {1,....365}. And then there's the issue.

S=365^n

This because the list of future birthdays of n people was its test point; therefore m points will be in the sequence so each point contains 365 distinct outcomes. The probability function P for \Omega is that any event is likely to happen in 365 days.

P(x)=\frac{1}{365^{n}}

if x is between 1 and 365 as well as the occurrence is just all similarly possible

In point i:

That somebody mentions their birthday throughout the party

Guess I was born on day b. Therefore the consequence of "x is in A" is "b is now in the series of x," which is to say, b = bk for some amount k approximately 1 and n.

In point ii:

Any 2 persons share the same birthday at this party". A result x is in B" means which "two of entries in x are same." This means that perhaps the outcome x is in B if or only if bj = bk is in B of two numbers j, and k of 1, of two. , no, n.

In point iii:

Many three students share the same birthday with both the party. The consequence is x at the level of C only when bj = bk = bl at three (different) indices, j, k, l, 1. , no, n.

6 0
2 years ago
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