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3 years ago

Solve for v. 14 − 10v + 11 = 20v + 5(–7v − 11) v =

Mathematics

2 answers:

AlexFokin [52]3 years ago

7 0

Answer:

v = -16

Step-by-step explanation:

→Distribute the 5 to (-7v - 11):

14 - 10v + 11 = 20v - 35v - 55

→Add like terms:

25 - 10v = -15v - 55

→Add 15v to both sides:

25 + 5v = -55

→Subtract 25 from both sides:

5v = -80

→Divide both sides by 5:

v = -16

Svetllana [295]3 years ago

3 0

Answer:

$\boxed{v = - 16}$

Step-by-step explanation:

$= > 14 - 10v + 11 = 20v + 5( - 7v - 11) \\ \\ = > 14 + 11 - 10v = 20v + (5 \times ( - 7v)) - (5 \times 11) \\ \\ = > 25 - 10v = 20v - 35v - 55 \\ \\ = > 25 - 10v = - 15v - 55 \\ \\ = > 25 - 10v + 15v = - 55 \\ \\ = > 25 + 5v = - 55 \\ \\ = > 5v = - 55 - 25 \\ \\ = > 5v = - 80 \\ \\ = > v = - \frac{80}{5} \\ \\ = > v = - 16$

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The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$