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sweet [91]
3 years ago
10

A special paint requires a mixture of paints: A, B and C. The ratio is: 60% A, 25% B, and 15% C. If you want 20 gallons of the s

pecial color, how many gallons of paint A will you need?
Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

20 \times .6 = 12
12 gallons
larisa86 [58]3 years ago
3 0

You would need 12 gallons of paint A. You can find this answer by finding what 60% of 20 is, and do that by multiplying 20 • (0.6). This is what gives you 12. Following that, you’ll need 3 gallons of C, and 5 gallons of B.


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.In a group of 40 people, 15 people are wearing
Oksi-84 [34.3K]

Answer:

It should be 5:10 or 5 people not wearing sneakers and 10 not wearing a blue shirt

Step-by-step explanation:

Well it quite simple 1st you have the total which is 40

next you look at the rest, 15 people wearing sneakers plus the 5 waering sneakers and blue shirt. now you have 15.

next you have 10 people wearing but shirts. if you add the numbers you have now you get this: 15+10=25.

Now that you have 25 you can just add numbers to get 25(in that case 10 and 5). whats how you get 5:10

hope this helps (barry_ary)

4 0
3 years ago
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The formula for the area of a regular polygon is A=1/2ap. What is the equation solved for a?
Galina-37 [17]
A= \frac{1}{2}ap \ \to \ 2A =ap \ \to \ \boxed{a= \frac{2A}{p}}
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3 years ago
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Eli packed 1,920 peanuts into 8 sacks. He packed an equal number of peanuts in each sack. How many peanuts did he pack into each
svlad2 [7]
D because one thousand nine hundred twenty divided by 8 equals two hundred and forty
8 0
2 years ago
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The measure of an angle is 117°. What is the measure of a supplementary angle?
ELEN [110]

Answer:

63°

Step-by-step explanation:

Supplementary angles add up to 180°

So the answer would be 180-117 = 63

6 0
3 years ago
The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
2 years ago
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