<h2>
The crime gets cleaned up at 2:00 PM</h2>
Step-by-step explanation:
Let the work be w.
Batman can clean up all of the crime in Gotham City in 8 hours working alone.

Robin can do the same job alone in 12 hours.

Robin starts work at 8:00 AM and Batman Joins at 10:00 AM.
Let the time of completion of work after Batman's joining be t.
We have time of working of Robin = t + 10:00 -8:00 = t + 2
So

After 4 hours of 10:00 Am work gets completed.
Time = 10:00 AM + 4 hours = 2:00 PM
The crime gets cleaned up at 2:00 PM
Answer:
35 minutes
Step-by-step explanation:
2 hrs 4 min= 160 min
3 hrs 15 min= 195 min
195-160=35
Solve for the area of the circular region first:
A = pi*r^2
A = pi*(30 mi)^2
A = 2827.43 mi^2
Density = 70000 people/2827.43 mi^2
Density = 24.76 = 25 people/mi^2 <--ANSWER Plz vote brainnliest
Answer:
(a) The average grade point is 2.5.
(b) The relative frequency table is show below.
(c) The mean of the relative frequency distribution is 0.3333.
Step-by-step explanation:
The given data set is
4, 4, 4, 3, 3, 3, 1, 1, 1, 1
(a)
The average grade point is



Therefore the average grade point is 2.5.
(b)

The relative frequency table is show below:
x f Relative frequency
4 3 
3 3
1 4 
(c)
Mean of the relative frequency distribution is


Therefore the mean of the relative frequency distribution is 0.3333.
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em>
<em>Please</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> full</em><em> </em><em>solution</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>