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FromTheMoon [43]
3 years ago
6

Determine whether each relationship is a function. State the domain and range of each relation.

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0
<h2>Hello!</h2>

The answer is:

The relation is not a function

Domain: {3,2,1}

Range: {0,1,4,5}

<h2>Why?</h2>

Since the value 3 (domain) has two values at the output (0 and 1), the relation is not a function.  A function only exists when there is exactly a output value for each input, if there is more than one output for each input, the relation is not a function.

For this case, 3 (domain) has two outputs (0 and 1), so the relation is not a function.

Have a nice day!

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Find the 61st term of -12, -28, -44,
Citrus2011 [14]

Answer:

a_{61}=-972

Step-by-step explanation:

<u>Arithmetic Sequences</u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the first terms of a sequence:

-12, -28, -44,...

Find the common difference by subtracting consecutive terms:

r = -28 - (-12) = -16

r = -44 - (-28) = -16

The first term is a1 = -12. Now we calculate the term n=61:

a_{61}=-12+(61-1)(-16)

a_{61}=-12-60*16=-12-960

\mathbf{a_{61}=-972}

6 0
3 years ago
Im confused someone help :(
denpristay [2]

Answer:

Step-by-step explanation

5 0
3 years ago
The product of two consecutive whole numbers is less than the sum of the square of the smaller number and 13
Norma-Jean [14]

Answer: a<13

Step-by-step explanation:

a*(a+1)<a^2+13

a^2+a<a^2+13

subtract a^2 from both sides:

a<13

8 0
4 years ago
The product of 7/16, 4/3, and 1/2 is
Eva8 [605]
First, we have two multiply two fractions (7/16 x 4/3) which we do top x top and bottom x bottom which gives us 28/48 

Second, we do 28/48 x 1/2 which is 28/96.

Lastly, we simplify 28/96 which gives us 7/24
4 0
4 years ago
Measure of each side of an equilateral triangle is 12cm. It's area is given by
telo118 [61]

Answer:

D

Step-by-step explanation:

The area (A) of an equilateral triangle is calculated as

A = \frac{s^2\sqrt{3} }{4} ← s is length of a side

Here s = 12, thus

A = \frac{12^2\sqrt{3} }{4}

  = \frac{144\sqrt{3} }{4}

  = 36\sqrt{3} → D

4 0
4 years ago
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