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Paul [167]
3 years ago
9

Find the standard form of the equation of the parabola with a focus at (-7, 0) and a directrix at x = 7.

Mathematics
2 answers:
Volgvan3 years ago
8 0

x = 1/(4p)*y^2

x = 1/(4*-7)*y^2

x = -1/28*y^2

34kurt3 years ago
5 0

Answer:

<em>y^2 = -28x.</em>

Step-by-step explanation:

The general form for this type of parabola is y^2 = 4ax where the focus is at (a,0)  and the directrix is x = -a.

So substituting we get

y^2 = 4 * -7 * x

y^2 = -28x

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PQ and PT are secants intersect outside a circle.

<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

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