The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis ⇒ 2nd answer
Step-by-step explanation:
The vertex form of a quadratic function is f(x) = a(x - h)² + k, where
- (h , k) are the coordinates of its vertex point
- The axis of symmetry of it is a vertical line passes through (h , 0)
- The minimum value of the function is y = k at x = h
∵ f(x) = a(x - h)² + k
∵ f(x) = (x - 2)² + 1
∴ a = 1 , h = 2 , k = 1
∵ The axis of symmetry of f(x) is a vertical line passes through (h , 0)
∴ The axis of symmetry of f(x) is a vertical line passes through (2 , 0)
∵ Any vertical line is parallel to y-axis
∴ The axis of symmetry of f(x) is a vertical line parallel to y-axis and
passes through (2 , 0)
The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis
Learn more:
You can learn more about quadratic function in brainly.com/question/9390381
#LearnwithBrainly
Answer:
C
Step-by-step explanation:
trust
7/2= radius (3.5)
V=πr2^<span>h
V=</span><span>π3.52*12
V= 461.81 </span>
Firstly,
thanks for posting this.
81 = 9x9 or 9 squared so at this stage I'm guessing the last two.
x^ 8 = (x^ 4) x (x^ 2) (its called the multiplication rule of indices).
Okay I have approx 14 mins to answer.
No panic
√ 81.x^8 x <span>√ y^5
</span>√ (9x^2 x 9x^6) x <span>√ y^5
</span>= 9x x <span>√ 9x^6 x </span><span>√ y^5
</span>did I just gain time?
√ 9x^6 = <span>√ </span>3x ^3 x <span>√ 3x ^ 3
</span>or 2 . √ 3x^3. <span>√ y^5
</span>more time
okay, so that wasnt successful.
√ 9x^6 =<span>√ </span> (3x^2) x <span>√ </span>(3x^4)
