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____ [38]
3 years ago
12

Find 6 tenths of 80cm

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

6/10 of 80 is 48

Anton [14]3 years ago
3 0

Answer:

The best thing to do here is to find 1/10th then multiply.

To do this, divide your number (80) by 10

80/10= 8

As you're looking for sixth tenths, you need to multiply this by 6

8*6= 48

Therefore, six tenths of 80cm is 48cm

Hope this helps :) 

Read more on Brainly.com - brainly.com/question/850582#readmore

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Morgarella [4.7K]

a) (0.17 ac)×(126 min/ac) = 21.42 min

b) I can mow 1/126 ac/min; you can mow 1/117 ac/min. Together, we can mow at a rate that is the sum of these:

... (1/126 + 1/117) ac/min = (117 + 126)/(126×117) = 243/14,742 ac/min

Then it will take 14,742/243 min/ac × 0.17 ac/lawn ≈ 10.31 min/lawn

5 0
3 years ago
Given that ∠CEA is a right angle and bisects ∠CEA, which statement must be true?
loris [4]
Given that ∠CEA is a right angle which has been bisected by BE, then:
∠CEB=∠BEA
thus each angle will be complementary to each other, hence the size will be:
90/2=45°
hence the correct statement.
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8 0
3 years ago
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What are the apparent zeros of the function graphed above ?
gregori [183]

Answer:

-2,1,4

Step-by-step explanation:

we have

y=x^{3}-3x^{2} -6x+8

we know that

The zeros of the function are the values of x when the values of the function is equal to zero

In this problem the apparent zeros are

For x=-2

y=0

For x=1

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For x=4

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3 0
3 years ago
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The number in each column are related. The goal is to determine how they are related, determine which numbers belongs in the bla
andre [41]

Answer:

If you cube the numbers in the left column, you get the numbers in the right column! We can figure this out by understanding that 1^3 = 1, 3^3 = 27, and 6^3 = 216. Then it all falls into place!

1 -> 1

2 -> 8

3 -> 27

5 -> 125

6 -> 216

11 -> 1331

8 -> 512

10 -> 1000

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p -> p^{2}

\sqrt{q} -> q

8 0
3 years ago
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Help ASAP Please
aleksklad [387]

The probability that a student uses the Internet, given that he or she is in eighth grade is 8/13 or 0.66

<u>Step-by-step explanation:</u>

<u>From the table shown:</u>

  • The students in the eighth grade = 13
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P(student uses the Internet in eighth grade) = P(eighth grade students using internet) / P(total students in the eighth grade)

⇒ 8/13

⇒ 0.66

6 0
3 years ago
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