the second one
Step-by-step explanation:
because if you see good the second one have the dimensional in the same way
Answer:
C
Step-by-step explanation:
The 6 comes from the 24(6*4=24)
The 3 comes from the 12(3*4=12)
The 4 is common
Answer:
u = -5/9
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-3(u + 2) = 5u - 1 + 5(2u + 1)
<u>Step 2: Solve for </u><em><u>u</u></em>
- Distribute: -3u - 6 = 5u - 1 + 10u + 5
- Combine like terms: -3u - 6 = 15u + 4
- Add 3u to both sides: -6 = 18u + 4
- Subtract 4 on both sides: -10 = 18u
- Divide 18 on both sides: -10/18 = u
- Simplify: -5/9 = u
- Rewrite: u = -5/9
<u>Step 3: Check</u>
<em>Plug in u into the original equation to verify it's a solution.</em>
- Substitute in <em>u</em>: -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
- Multiply: -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
- Add: -3(13/9) = -25/9 - 1 + 5(-1/9)
- Multiply: -13/3 = -25/9 - 1 - 5/9
- Subtract: -13/3 = -34/9 - 5/9
- Subtract: -13/3 = -13/3
Here we see that -13/3 does indeed equal -13/3.
∴ u = -5/9 is a solution of the equation.
A) See picture for the table.
To make the table, multiply 47774 by 1.5% to get total that have diabetes and multiply 5855 by 2.5% to get total unemployed that have it, then using subtraction fill in the other squares of the table.
B)
Hypothesis:
H0: No association between employment and diabetes.
H1: Association between the two
Using a graphing calculator or Excel, run a chi-test.
Chi squared equals 31.844 with 1 degrees of freedom.
The two-tailed P value is less than 0.0001
With this information we can reject the null hypothesis and conclude there is an association between diabetes and employment.
C)
Although there is a statistical significance, there really is no practical significance between an incidence rate of 1.5 or 2.5%
50 =2×5×5
125=5×5×5
Hoghest common factor = 5×5
=25
