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ruslelena [56]
3 years ago
15

A cable is attached to the top of a 28-foot utility pole. The cable is fastened to the ground at a point 21 feet from the base o

f the pole. Find the length of the cable.
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

Length of the cable (H) = 35 foot

Step-by-step explanation:

Given:

Height of the pole (P) = 28 Foot

Distance from the pole (B) = 21 Foot

Find:

Length of the cable (H) = ?

Computation:

According to the Pythagoras theorem:

H = \sqrt{P^2+B^2}

Length\ of\ the\ cable = \sqrt{(Height\ of\ the\ pole)^2+(Distance\ from\ the\ pole)^2}

Length\ of\ the\ cable =\sqrt{28^2+21^2}\\\\ Length\ of\ the\ cable =\sqrt{784+441}\\\\Length\ of\ the\ cable=\sqrt{1,225} \\\\Length\ of\ the\ cable = 35

Length of the cable (H) = 35 foot

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The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
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These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

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Now plug in some value to the right of x = 0. I'm going to pick x = 1
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Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
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Plug in x = 5 to find that
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