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tiny-mole [99]
3 years ago
11

What is the quickest way to remove filters from a worksheet?

Computers and Technology
1 answer:
cricket20 [7]3 years ago
5 0

Answer:If you want to completely remove filters, go to the Data tab and click the Filter button, or use the keyboard shortcut Alt+D+F+F.

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You cite them correctly and that the statistics are real.

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Which tab automatically becomes available after inserting a text box? Drawing Tools Insert Text Box Tools Shape Tools
In-s [12.5K]

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insert text box

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Which of the following is true? Group of answer choices worst case time of Heapsort is better than worst cast time of Quicksort
Sav [38]

Answer:

Worst case time of Heapsort is better than worst case time of Quicksort.

Explanation:

Worstcase of Heapsort is nlog(n). Worstcase time of Quicksort is (n^2). Heapsort is comparison based sorting algorithm. Heapsort divides input into sorting. It is a selection sort in which we send maximum inputs for maximum elements at end. Quicksort is divide and conquer algorithm. It is considered as efficient sourcing algorithm.

8 0
3 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
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