Who is the best basketball player ever... if you do not say lebron do not comment

Modify an array's elements Write a for loop that iterates from 1 to numberSamples to double any element's value in dataSamples t

ValentinkaMS [17]

Answer:

See explaination for program code

Explanation:

%save as AdjustMinValue.m

%Matlab function that takes three arguments

%called number of samples count, user samples

%and min vlaue and then returns a data samples

%that contains values which are double of usersamples

%that less than min vlaue

%

function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)

dataSamples=userSamples;

%for loop

for i=1:numberSamples

%checking if dataSamples value at index,i

%is less than minValue

if dataSamples(i)<minValue

%set double of dataSamples value

dataSamples(i)= 2*dataSamples(i);

end

Sample output:

Note:

File name and calling method name must be same

--> AdjustMinValue(4, [2,12,9,20],10)

ans =

4 12 18 20

3 0

3 years ago

Write a program that unpickle's employee dictionary and while reading from the dictionary, it allows users to lookup an employee

melamori03 [73]

Answer:

Check the explanation

Explanation:

from Employee import *

import pickle

import random

def unpickle_employee(filename):

file=open(filename,'rb')

data=pickle.load(file)

file.close()

return data

def pickle_employee(data,filename):

file=open(filename,'wb')

pickle.dump(data,file)

file.close()

if __name__=='__main__':

filename="Employees.dat"

'''

E=Employee("Ajay",1,"R&D","Manager")

data={}

data[1]=E

pickle_employee(data,filename)

'''

data=unpickle_employee(filename)

while True:

print("\nData In Employee.dat")

for d in data:

print("Employe data: ",data[d].get_name(),"({},{},{})".

format(data[d].get_id_number(),data[d].get_department(),data[d].get_job_title()))

print("\n\n\t\tMenu")

print("To add new Employee, Enter a")

print("To update any Employee, Enter u")

print("To delete any Employee, Enter d")

print("Enter anything to quit")

choice=input("Enter: ")

if choice=='a':

id_number=random.randrange(100,200,1)

while id_number in data:

id_number+=1

if id_number>=200:

id_number=100

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E

elif choice=='u':

id_number=int(input("Enter the Employee id_number to update: "))

for d in data:

print(id_number,d,d==id_number)

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

print("\nPlease Enter the details")

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E

else:

print("Employee doesn't exist\n")

elif choice=='d':

id_number=int(input("Enter the Employee id_number to delete: "))

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

choice=input("\nPlease Enter y to confirm, anything else to cancel: ")

if choice=='y':

del data[id_number]

else:

print("Employee doesn't exist\n")

else:

break

pickle_employee(data,filename)

7 0

3 years ago

Consider a set of mobile computing clients in a certain town who each

poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - - cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we find the max flow in N

⇒ connecting cl-i clients to bs-j stations

like (cl-i, bs-j) = 1

if f(cl-i, bs-j) = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected to bs-j(stations) f(cl-i,bs-j) = 1 (o otherwise)

f(bs-j,t) = no of clients (cl-i) connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0

3 years ago

Which term best describes a popular marketing strategy that centers

IceJOKER [234]

Answer:

Customer Relationship Management (CRM).

Explanation:

CRM is an acronym for customer relationship management and it typically involves the process of combining strategies, techniques, practices and technology so as to effectively and efficiently manage their customer data in order to improve and enhance customer satisfaction.

This ultimately implies that, these employees are saddled with the responsibility of ensuring the customer are satisfied and happy with their service at all times.

Marketing can be defined as the process of developing promotional techniques and sales strategies by a firm, so as to enhance the availability of goods and services to meet the needs of the end users or consumers through advertising and market research. It comprises of all the activities such as, identifying, anticipating set of medium and processes for creating, promoting, delivering, and exchanging goods and services that has value for customers.

Basically, CRM involves understanding customer needs, building and maintaining healthy long-term relationships with them, in order to add value or scale up your business.

Hence, customer relationship management (CRM) is one of the popular marketing strategy that is mainly based on the acquisition, enhancement, and retention of long-term relationships that add value for the organization and the customer.

8 0

2 years ago

four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,

marshall27 [118]

Answer:

n = 3

$l$ = 1

$m_l$ = 1

$m_s=+1/2$

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

1s² 2s² 2p⁶ 3s² 3p⁶ : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

n = 3

$l$ = 1 (orbitals s correspond to $l$ = 0, orbitals p correspond to $l$ = 1, orbitals d, correspond to $l$ = 2 , and orbitals f correspond to $l$ = 3)

$m_l$ can be -1, 0, or 1 (from - $l$ to + $l$ )

the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

(3, 1, -1 +1/2)
(3, 1, -1, -1/2)
(3, 1, 0, +1/2)
(3, 1, 0, -1/2)
(3, 1, 1, +1/2)
(3, 1, 1, -1/2)

Hence, the correct choice is:

n = 3

$l$ = 1

$m_l$ = 1

$m_s=+1/2$

5 0

3 years ago