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SpyIntel [72]
4 years ago
6

Which expression is equivalent to StartFraction negative 9 x Superscript negative 1 Baseline y Superscript negative 9 Baseline O

ver negative 15 x Superscript 5 Baseline y Superscript negative 3 Baseline EndFraction? Assume x not-equals 0, y not-equals 0. StartFraction 3 Over 5 x Superscript 5 Baseline y cubed EndFraction StartFraction 3 Over 5 x Superscript 6 Baseline y Superscript 6 Baseline EndFraction StartFraction 5 Over 3 x Superscript 5 Baseline y cubed EndFraction StartFraction 5 Over 3 x Superscript 6 Baseline y Superscript 6 Baseline EndFraction
Mathematics
2 answers:
kirill115 [55]4 years ago
7 0

Answer:

Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3?  Assume x =/ 0 y =/ 0

Step-by-step explanation:

The actual answer is B

3/5x^6y^6

on edg just took the test myself and B is the correct answer...  Good Luck!!!

Lyrx [107]4 years ago
5 0

Answer:

A on edge

Step-by-step explanation:

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How many meters are there in 234 cm?
Reika [66]
There are 100 cm for every 1 meter    
\frac{1 m}{100 cm}
so insert the 234 as the numerator and simplify
\frac{234cm}{100cm}
The simplified form of the equation is 2.34
There is 2.34 meters in 234 cm

6 0
3 years ago
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My boss told me that I am getting 150% raise I was making $12 per hour what is new my hourly pay
Semmy [17]

Answer:

$18

Step-by-step explanation:

100% = $12

50% = $6

$12 + $6 = $18

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3 years ago
2 plus 2 = u btw it’s just 4
Lisa [10]

Answer:

Okay

Step-by-step explanation:

5 0
3 years ago
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What is the completely factored form of the expression 16X2 +18X+32
lina2011 [118]

ANSWER

2(8 {x}^{2}  + 9x + 16)

EXPLANATION

The given expression is

16 {x}^{2}  + 18x + 32

The greatest common factor is 2.

We factor 2 to obtain:

2(8 {x}^{2}  + 9x + 16)

The expression in the parenthesis is prime.

This means that the quadratic expression in the parenthesis cannot be factored.

Hence the completely factored form is:

2(8 {x}^{2}  + 9x + 16)

7 0
4 years ago
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I need help with this question please
lutik1710 [3]

Answer:

<u>Average</u><u> </u><u>rate</u><u> </u><u>of</u><u> </u><u>change</u><u> </u><u>is</u><u> </u><u>-</u><u> </u><u>1</u><u>/</u><u>6</u><u> </u><u>or</u><u> </u><u>-</u><u>0</u><u>.</u><u>1</u><u>6</u><u>6</u><u>…</u>

Step-by-step explanation:

{ \tt{f(x) =  \frac{1}{x - 5} }}

f(-1):

{ \tt{f( - 1) =  \frac{1}{( - 1 - 5)} }} \\  = { \tt{ -  \frac{1}{6} }}

f(3):

{ \tt{f(3) =  \frac{1}{3 - 5} }} \\  = { \tt{ -  \frac{1}{2} }}

Average rate of change:

= { \bf{ \frac{f(3) - f(-1)}{2} }}

{ \tt{ =  \frac{ -  \frac{1}{2}  - ( -  \frac{1}{6} ) }{ 2 } }} \\   \\  = { \tt{ -  \frac{1}{6} }}

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3 years ago
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