1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sphinxa [80]
2 years ago
9

Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t

he transformation that shows it is congruent to ABCD.
E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)
a translation 7 units right
E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)
a reflection across the y-axis
E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)
a reflection across the x-axis
E(4, 4), F(8, 3), G(10, 6), and H(8, 6)
a translation 5 units down

arrowBoth

arrowBoth

arrowBoth

arrowBoth
Reset Next
Previous3 Next Transformations and Congruence: Mastery Test Submit Test Tools Info
© 2019 Edmentum. All rights reserved.

Mathematics
1 answer:
Maru [420]2 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

First plot points A, B, C and D on the coordinate plane and connect them to get quadrilateral ABCD. Then plot the vertices E, F, G, H of the quadrilateral EFGH in each case.

For each of these cases there are attached diagrams

1 case - reflection acraoss the x-axis

2 case - translation 5 units down

3 case - reflection across the y-axis

4 case - translation 7 units right

You might be interested in
What is the equation of the graph
AveGali [126]

Answer:

y = 2x^2 + 1

Step-by-step explanation:

The graph you see there is called a parabola. The general equation for the graph is as below

y = a*x^2 + b

To find the equation we need to find the constants a and b. The constant b is just how much we're lifting the parabola by. Notice it's lifted by 1 on the y axis.

To find a it's a little more tricky. Let's use the graph to find a value for a by plugging in values we know. We know that b is 1 from the previous step, and we know that when x=1, y=3. Let's use that!

3 = a * (1)^2 + 1\\2 = a

Awesome, we've found both values. And we can write the result.

y = 2x^2 + 1

I'll include a plotted graph with our equation just so you can verify it is indeed the same.

5 0
2 years ago
Who can do 20 assignments in math for me rn needs to b finish in 5 hours?
GREYUIT [131]

u need to finish 4 assignments in 1 hour

5 0
3 years ago
To solve the inequality 9x >-4, the inequality sign must be reversed.
Anna35 [415]

Answer:

false

Step-by-step explanation:

you only need to reverse the sign when you are dividing by a negative number

7 0
3 years ago
Read 2 more answers
A woman won a 4000​-m race with a time of 12.089 min. What was her​ rate?
Blizzard [7]

Answer:

330.88 m/min  

Step-by-step explanation:

rate = distance/time

        = 4000 /12.089

        = 330.88 m/min

8 0
3 years ago
I will give brainliest answer
adell [148]

Answer: A=351.68 cm²

Step-by-step explanation:

To find the area of the shaded region, we would subtract the area of the circle by the area of the inner circle.

Area of Circle

A=\pi r^2

A=\pi (11)^2

A=121\pi

Area of inner (white) circle

A=\pi r^2

A=\pi (3)^2

A=9\pi

Now that we have the area to the circle and inner circle, we would subtract to find the area of the shaded region.

A=121\pi -9\pi

A=112\pi

A=351.68 cm^2

3 0
3 years ago
Other questions:
  • Can someone help me with this?
    5·1 answer
  • Please help!!!!
    12·1 answer
  • 5,ooo invested 5 years 3% interest compounded continuously
    11·1 answer
  • Please answer this question
    11·1 answer
  • Find all the zeros of the equation<br> -2x^4+27x^2+1200=0
    9·1 answer
  • Identify the property that the statement illustrates
    12·1 answer
  • Find the median of data set. Round it to the nearest tenth.​
    12·2 answers
  • Find the area of the polygon.
    10·1 answer
  • Please help! I cant figure this out!
    14·1 answer
  • Plzzzz help!!! I will give brainlist for the answer.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!