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Nitella [24]
3 years ago
8

Which is the more reasonable measurement of the distance between the tracks on a railroad: 1.435 ⋅ 10−3 mm or 1.435 ⋅ 103 mm? Ju

stify your answer.
Mathematics
2 answers:
SVEN [57.7K]3 years ago
5 0
The best answer is 1.435 ·103 because while they both are really small for a rail road track that one is bigger. the final answer for that is 147.805mm.
masya89 [10]3 years ago
4 0

Answer:

id say the second on the not negivtive so yeah

Step-by-step explanation:

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For every 21 litres of petrol a car can run for 80 km. How much petrol do you need (to 1 DP) to ensure the car has enough petrol
geniusboy [140]

Answer:

1

Step-by-step explanation:

5 0
2 years ago
Giving out 60 points
Yuki888 [10]
If the markers are 4.5 inches away on the map, and 2.5 inches represents 10 miles, then we need to make ratios we can work with.

Inches / Miles: 

4.5 / x
2.5 / 10

Now, we can cross multiply to end up with:

2.5 * x = 4.5 * 10

Simplify:

2.5x = 45

Divide 2.5 on each side:

2.5x / 2.5 = 45 / 2.5

Simplify:

x = 45 / 2.5
x = 18

Awesome! Now we have a real ratio on the real distance of the markers.

<span>2.5 : 10  &  4.5 : </span><span>18.
</span>
18 miles is the actual distance between the two markers.

Hope I could help! If my math is wrong, or it isn't the answer you are looking for, please let me know!
<span>Have a good one!</span>
6 0
3 years ago
8 to the power of -3 / 8 to the power of 6
MArishka [77]

the answer is 0.000000007

4 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
What is 5/18 + 7/12?
Flauer [41]
5/18+7/12

=10/36+21/36

=31/36
8 0
3 years ago
Read 2 more answers
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