Complete the sentence.

The DNS server at your headquarters holds a standard primary zone for the abc domain. A branch office connected by a slow WAN li

mafiozo [28]

Answer:

In the SOA tab of the zone's Properties dialog box, increase the refresh interval.

Explanation:

5 0

3 years ago

Write, compile, and test the MovieQuoteInfo class so that it displays your favorite movie quote, the movie it comes from, the ch

Irina18 [472]

Using the knowledge of computational language in JAVA it is possible to write a code that removes your favorite phrase from the movie. It consists of two classes in which one is driver code to test the MovieQuoteInfo class.

<h3>Writing code in JAVA:</h3>

public class MovieQuoteInfo { //definition of MovieQuoteInfo class

//All the instance variables marked as private

private String quote;

private String saidBy;

private String movieName;

private int year;

public MovieQuoteInfo(String quote, String saidBy, String movieName, int year) { //parameterized constructor

super();

this.quote = quote;

this.saidBy = saidBy;

this.movieName = movieName;

this.year = year;

}

//getters and setters

public String getQuote() {

return quote;

}

public void setQuote(String quote) {

this.quote = quote;

}

public String getSaidBy() {

return saidBy;

}

public void setSaidBy(String saidBy) {

this.saidBy = saidBy;

}

public String getMovieName() {

return movieName;

}

public void setMovieName(String movieName) {

this.movieName = movieName;

}

public int getYear() {

return year;

}

public void setYear(int year) {

this.year = year;

}

//overriden toString() to print the formatted data

public String toString() {

String s = quote+",\n";

s+="said by "+this.saidBy+"\n";

s+="in the movie "+this.movieName+"\n";

s+="in "+this.year+".";

return s;

}

}

Driver.java

public class Driver { //driver code to test the MovieQuoteInfo class

public static void main(String[] args) {

MovieQuoteInfo quote1 = new MovieQuoteInfo("Rosebud", "Charles Foster Kane", "Citizen Kane", 1941);//Create an object of MovieQuoteInfo class

System.out.println(quote1); //print its details

}

}

See more about JAVA at brainly.com/question/12975450

#SPJ1

7 0

2 years ago

Write, compile and test (show your test runs!) program that calculates and returns the fourth root of the number 81, which is 3.

lys-0071 [83]

Answer:

I am writing a JAVA program. Let me know if you want the program in some other programming language.

public class FourthRoot{ //class to calculate fourth root of 81

public static void main(String[] args) { //start of main() function body

double square_root; //declares to hold the fourth root of 81

double number=81; // number is assigned the value 81

/* calculates the fourth root of number using sqrt() method twice which means sqrt() of sqrt(). This is equivalent to pow(number,(0.25)) where pow is power function that computes the fourth root by raising the number 81 to the power of 0.25 which is 1/4 */

square_root=Math.sqrt(Math.sqrt(number));

//displays the fourth root of 81 i.e. 3

System.out.println("Fourth Root of 81 is "+ square_root); } }

Explanation:

The program is well explained in the comments given along with each statement of the program . Since it was the requirement of the program to user Math.sqrt() method so the fourth root of number= 81 is computed by taking the sqrt() of 81 twice which results in the fourth root of 81 which is 3.

So the first sqrt(81) is 9 and then the sqrt() of the result is taken again to get the fourth root of 81. So sqrt(9) gives 3. So the result of these two computations is stored in square_root variable and the last print statement displays this value of square_root i.e. the fourth root of number=81 which is 3.

Another way to implement the program is to first take sqrt(81) and store the result in a variable i.e. square_root. After this, again take the sqrt() of the result previously computed and display the final result.

public class FourthRoot{

public static void main(String[] args) {

double square_root;

double number=81;

square_root=Math.sqrt(number);

System.out.println("Fourth Root of 81 is: "+ Math.sqrt(square_root)); } }

The program along with its output is attached in a screenshot.

5 0

4 years ago

Suppose that a computer can run an algorithm on a problem of size 1,024 in time t. We do not know the complexity of the algorith

Setler79 [48]

Answer:

Time Complexity of Problem - O(n)

Explanation:

When n= 1024 time taken is t. on a particular computer.

When computer is 8 times faster in same time t , n can be equal to 8192. It means on increasing processing speed input grows linearly.

When computer is 8 times slow then with same time t , n will be 128 which is (1/8)th time 1024.

It means with increase in processing speed by x factor time taken will decrease by (1/x) factor. Or input size can be increased by x times. This signifies that time taken by program grows linearly with input size n. Therefore time complexity of problem will be O(n).

If we double the speed of original machine then we can solve problems of size 2n in time t.

5 0

4 years ago

Which option describes a balanced slide?

Umnica [9.8K]

Answer: a slide with a size 18 font and five images

Explanation:

the text isnt that big to overpower the images and vise versa

4 0

3 years ago