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dlinn [17]
3 years ago
8

How to solve probabilities

Mathematics
2 answers:
melomori [17]3 years ago
7 0
The  probability of each sample point must be equal to 1/2
valina [46]3 years ago
5 0

You can solve many simple probability problems just by knowing two simple rules:

<span> The probability of any sample point can range from 0 to 1.<span> The sum of probabilities of all sample points in a sample space is equal to 1. </span></span>

The following sample problems show how to apply these rules to find (1) the probability of a sample point and (2) the probability of an event.

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4 1/4 divided by 1 1/2
MakcuM [25]
Hello, Briana so when dividing fractions, its best to put them in decimal form so that you can divide or multiply better. Now having this in mind, 4.25 divided by 1.5 becomes the new equation and using simple math on a calculator, we can conclude that the answer to this question is 1.7 in decimal form or 1 and 7 over 10 in fraction form. Hope this helped, if you have any questions, please ask!
3 0
3 years ago
Find the total volume. Please show your work.​
elena-s [515]

Answer:

Step-by-step explanation:

You have a half sphere and a cylinder.

Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.

For cylinder:

 radius r = 5 m

 height h = 6 cm = 0.06 m

 volume = πr²h = π(5²)(0.06) = 1.5π m³

For sphere:

 radius r = 5 m

 volume of sphere = (4/3)πr³

 volume of half sphere =  (2/3)πr³ = (2/3)π5³ = (250/3)π m³

Total volume = 1.5π + 250π/3 ≅ 266.5 m³

4 0
2 years ago
Is −3 a solution to the equation 3 − 5 = 4+ 2? Explain.
Vesnalui [34]

Answer:

There is no variable so -3 therefore cannot be a solution to this.

8 0
3 years ago
Read 2 more answers
Is the circle inside the hexagon or hexagon inside the circle?
nexus9112 [7]

It could be either, we need more info. How big are each? If it doesn't say, then it's a trick question. Throw Schrodinger's cat at it or something.

8 0
3 years ago
Which is the solution set for –7 ≤ 4x + 1 ≤ 5?<br><br> I added a picture !
Oksi-84 [34.3K]
-7\leq4x+1\leq5\ \ \ \ |subtract\ 1\\\\-7-1\leq4x+1-1\leq5-1\\\\-8\leq4x\leq4\ \ \ \ |divide\ by\ 4\\\\-8:4\leq4x:4\leq4:4\\\\\boxed{-2\leq x \leq1\Rightarrow x\in[-2;\ 1]}

\boxed{x\geq-2\ and\ x\leq1}\to\answer{\boxed{C}}
6 0
3 years ago
Read 2 more answers
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