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Andreas93 [3]
3 years ago
8

One half of a number decreased by 16

Mathematics
2 answers:
MAXImum [283]3 years ago
6 0
Hey there!

"One half of a number" will be a number (x) divided by 2. This can also be shown as "0.5x" or "1/2x", whichever you prefer. 

"...decreased by 16" will be "– 16", making your full equation 0.5x – 16. Remember that terms like remainder, difference, and fewer will always mean subtraction. 

Hope this helped you out! :-)
elena-14-01-66 [18.8K]3 years ago
3 0
1/2x-16 is an equation that can be used to represent this. The 1/2x represents the one half of a number and the -16 represents the decreased by 16.
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irinina [24]
Sorry for the hand writing. But you want to factor out a 4y^2 which will result in (9y^2-1). Then you will factor out the equation in parentheses to (3y-1)(3y+1). Don’t forget to put the 4y^2 out front!

8 0
3 years ago
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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
Read 2 more answers
Solve the square root equation.
Neko [114]

Answer:

x = 9

Step-by-step explanation:

subtract 5 from 11 with = 6

divide by -2 which = -3

square your answer so (-3)² = 9

4 0
2 years ago
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How do i solve 4x - 2y = 22 and 2x + 4y = 6 using substitution and elimination?
Fiesta28 [93]

substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.

Consider the above two equations.

Take equation 1, which is 4x-2y=22 => x=(22+2y)/4

substitute the x value gained above in equation 2.

so, 2((22+2y)/4)+4y=6

22+2y+8y=12 => 10y = -10 => y= -1.

Substitute y= -1 in x value obtained in the beginning.

So, x= (22 - 2)/4 => 5.

There fore, x= 5 and y= -1

Hope it helps.

5 0
3 years ago
The question is in the picture.
nordsb [41]
The first bullet is the answer
7 0
3 years ago
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