The graph is misleading because the year’s interval is not constant.
The first year to the second year, the gap is 1 year; in the second to the
third year, the gap is 2; in the third to the fourth year is 4; and the fourth
to the fifth year is 6.
just add the whole numbers and add negative infront -16+-27= -43
Asking the Math Gods...
B. 204in^2
<span><span>Surface Area (SA) =√3 * a²+ 3 * a * h</span>2 </span><span />
Answer:
There are 12 pentapods and 8 Tripods, which in total add up to 84 feet.
Step-by-step explanation:
Given that both the Tripods and the Pentapods have, at least, 3 feet (the Pentapods have 5), and that in total between both groups they add 20 heads and 84 feet, the following logical reasoning can be made:
If there are 20 heads, there are 20 Martians in all. Each of them has, at least, 3 feet, with which in principle the 20 Martians would add up to a total of 60 feet (20 x 3). Therefore, there is a surplus of 24 feet (84 - 60).
If the Pentapods have 2 feet more than the Tripods, the number of Pentapods in the total Martians is determined by that difference. Thus, if there are 24 feet left, there are 12 Pentapods (24/2).
Therefore, in the group of Martians there are 12 pentapods (12 x 5 = 60) and 8 Tripods (8 x 3 = 24), which in total add up to 84 feet (60 + 24).
The answer is B.
In order to add the two values together, you must find the least common multiple for the denominators. The denominators are 8 and 4, and the least common multiple of 8 and 4 is 8. Because you have to multiply 4 by 2 to get 8, you must also multiply 3 by 2 to get 6. This will give you 6/8.
