Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
green pepper, onion, tomato
= 2x, 5x, 9x
Number of cups = 96
therefore 2x + 5x + 9x = 96
16x=96
x= 96÷16 = 6
Onion = 5x
therefore answer = 6 x 5 = 30
C. 30 is the correct answer :)
The answer to this one is the 3rd one
Answer:
If the number of blue tiles in the bag is 180, then the probability of randomly drawing a red tile equal to 1/10.
Step-by-step explanation:
Total number of red tiles in a bag = 20
Let us assume the number of blue tiles in a bag = p
So, the total number of tiles in a bag = Red Tiles + Blue tiles
= 20 + p
Now, let us find the probability of drawing a red tile:
But, here the probability of drawing a red tile = 1/10
or, p = 180
Hence, if the number of blue tiles in the bag = 180, then the P Picking out a red tile ) is 1/10.
