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3 years ago

What is square root of 12 in simplified radical form?

2 answers:

6 0

Option A: 2 square root 3

Option B: 3 square root 2

Option C: 4 square root 3

Option D: 6 square root 2

Hope this helps!

zhenek [66]3 years ago

6 0

<span>I believe it is
√12=2</span>√3

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Write the solution to the given inequality in interval notation.

melomori [17]

The answer is [4,6) because a square bracket (closed) denotes that the lower bound is inclusive, and the parenthesis (open) denotes that the upper bound is exclusive.

As you can see on the number line, there is a closed dot on 4 and an open dot on 6.

8 0

3 years ago

State the property that justifies each statement:1. If 80 mA, then me = 802. If RS - TU and TU = YP, then RS = YP2.3. If 7x 28,

BabaBlast [244]

Question 3

if 7x = 28

divide both sides by 7

7x/7 = 28/7

x = 4

This is division property of equality

Question 1

if angle m is 80 degrees the m = 80 degrees

this can be a congruent angles or alternate angles are equal

this is symmetric property of equality

Question 5

m1 = 30 and mz1 = m2, then m2 = 30

this property is transitive property of equality

Question 2

if RS - TU and TU =YP, then RS = YP

this means you can substitute RS with YP

then we have our new expression as

YP - YP

this is substitution property of equality, this is because we are substituting a function with another function

4 0

1 year ago

Can anyone help me with calculus??

gogolik [260]

1. If $f(x)=(x+1)^4$ , then $f'(x)=4(x+1)^3$ . So $f'(1)=32$ .

2. With $x^2+y^2=1$ , we differentiate once with respect to $x$ and get

$\dfrac{\mathrm d}{\mathrm dx}[x^2+y^2]=\dfrac{\mathrm d}{\mathrm dx}1$

$2x+2y\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac xy$

Differentiate again with respect to $x$ and we get

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{y-x\frac{\mathrm dy}{\mathrm dx}}{y^2}$

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{y+\frac{x^2}y}{y^2}=-\dfrac{y^2+x^2}{y^3}=-\dfrac1{y^3}$

(where $y\neq0$ ).

3. Check the one-side limits where the pieces are split. For $f$ to be continuous everywhere, we need

$\displaystyle\lim_{x\to-1^-}f(x)=\lim_{x\to-1^+}f(x)=f(-1)$

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$

In the first case, we have

$\displaystyle\lim_{x\to-1^-}f(x)=\lim_{x\to-1}x+2=1$

$\displaystyle\lim_{x\to-1^+}f(x)=\lim_{x\to-1}x^2=1$

and $f(-1)=1$ , so it's continuous here.

In the second case, we have

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}x^2=1$

$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}3-x=2$

so $f$ is discontinuous at $x=1$ .

4. If $f(x)=3xe^x$ , then $f'(x)=3e^x+3xe^x=3e^x(1+x)[tex]. So [tex]f'(0)=3$ .

5. If $f(x)=(x+1)^2(x+2)^3$ , then $f'(x)=2(x+1)(x+2)^3+3(x+1)^2(x+2)^2=(x+1)(x+2)^2(5x+7)$ . So $f'(0)=28$ .

6. The average velocity over [1, 2] is given by

$\dfrac{s(2)-s(1)}{2-1}=(2^2+2)-(1^2+1)=4$

7. If $f(x)=\sin^2x$ , then $f'(x)=2\sin x\cos x=\sin2x$ . So $f'\left(\dfrac\pi4\right)=\sin\dfrac\pi2=1$ .

8. If $f(x)=\log_23x$ , then

$2^{f(x)}=3x\implies e^{\ln2^{f(x)}}=3x\implies e^{(\ln2)f(x)}=3x$

Differentiating, we get

$(\ln2)f'(x)e^{(\ln2)f(x)}=(\ln2)3xf'(x)=3\implies f'(x)=\dfrac1{(\ln2)x}$

So $f'(1)=\dfrac1{\ln2}$ .

9. If $f(x)=\dfrac1{x^2}$ , then $f'(x)=-\dfrac2{x^3}$ . So $f'(1)=-2$

10. If $f(x)=-\dfrac{6x}{e^x+1}$ , then $f'(x)=-\dfrac{6(e^x+1)-6xe^x}{(e^x+1)^2}=-\dfrac{6e^x(1-x)+6}{(e^x+1)^2}$ . So $f'(0)=-\dfrac{12}4=-3$ .

7 0

4 years ago

What is y in the equation 2/3 (2y+1) = 3/7 (2-y)

Alik [6]

Answer:

$y=\frac{4}{37}$

Step-by-step explanation:

$\frac{2}{3}(2y+1)=\frac{3}{7}(2-y)$

$\frac{4}{3}y+\frac{2}{3} =\frac{6}{7}- \frac{3}{7}y$

Add $\frac{3}{7}y$ on both sides and subtract $\frac{2}{3}$ on both sides.

$(\frac{3}{7}y- \frac{2}{3})+\frac{4}{3}y+\frac{2}{3} =\frac{6}{7}- \frac{3}{7}y+(\frac{3}{7}y- \frac{2}{3})$

$\frac{3}{7}y+\frac{4}{3}y=\frac{6}{7}-\frac{2}{3}$

Solve the fractions.

$\frac{(3)(3)+(7)(4)}{(7)(3)}y=\frac{(6)(3)-(7)(2)}{(7)(3)}$

$\frac{9+28}{21} y=\frac{18-14}{21}$

$\frac{37}{21}y =\frac{4}{21}$

Multiply by the reciprocal of the fraction with the variable to isolate the variable. The reciprocal is the inverted fraction.

$\frac{21}{37}*\frac{37}{21}y =\frac{4}{21}*\frac{21}{37}$

$y=\frac{4}{37}$

4 0

4 years ago

Read 2 more answers

Twice the number n is no less than 10 units from -1

Nataly [62]

This means that 2n is equal to or greater than -1 +10 or -1-10, which can be shown as 2n ≥ 9 and 2n ≥-11, and since 2n ≥11 encompasses both, we can therefore say 2n ≥-11 or n ≥ -5.5 by dividing both sides by 2

7 0

4 years ago