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Nadya [2.5K]
3 years ago
5

Please answer need now

Mathematics
1 answer:
topjm [15]3 years ago
4 0

Explanation:

A. When you examine the values in the table, you see the y-value is not proportional to the x-value. That is, 20/1 ≠ 26/2. However, you do notice that the y-values increase by 6 when the x-values increase by 1. <em>The ratio of these increases is the slope of the graph of the relation between y and x</em>.

Since the slope is 6, we might expect a value of 6×1 = 6 for x=1. However, the y-value for x=1 is 20, which is 14 more than what might be predicted by the slope. <em>This added extra is the y-intercept on the graph of the relation</em>.

The slope is 6 and the y-intercept is 14.

__

B. The slope is (26-20)/(2-1) = 6.

__

C. For x=1, the slope-intercept equation tells us ...

  y = 6x +b

  20 = 6·1 + b . . . . . . . . . . substitute (x, y) = (1, 20)

  20 -6 = 14 = b . . . . . . . . subtract 6 to find b

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Anumeha is mowing the lawns for a summer job. For every mowing job, she charges and initial fee of $10 plus a constant fee for e
ExtremeBDS [4]

Answer:

F(t) = 10 +5t

Step-by-step explanation:

Income equals the initial fee plus the hours worked times the hourly rate

We know the initial fee = 10

hours = t

hourly rate =r


F(t) = 10 + r*t

We know a 5 hour job is 35 dollars

35 = 10 + r*5

Subtract 10 from each side

35-10 = 10-10 +5r

25 = 5r

Divide by 5

25/5 = 5r/5

5 =r

The hourly rate is 5

F(t) = 10 +5t

8 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
If f(x)=3x-2,find f(8)-f(-5)
Alexandra [31]

To find both f(8) and f(-5), we will need to plug in their values for x and solve for each. Then, we can subtract them to find the final answer.

Finding f(8):

f(8) = 3(8) - 2

f(8) = 24 - 2

f(8) = 22

Finding f(-5):

f(-5) = 3(-5) - 2

f(-5) = -15 - 2

f(-5) = -17

Subtracting f(8) and f(-5):

f(8) - f(-5)

22 - - 17

22 + 17

39

Hope this helps!! :)

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3 years ago
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AlladinOne [14]
Use the GCF of the terms to write the expression as the product of two factors with integer coefficients.

-2x3 - 4x2 + 4x
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3 years ago
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Mama L [17]

I think the answer is D. But I am not sure if that's the right answer.

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