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jasenka [17]
3 years ago
15

The equation for line G is given by 5y = -2x - 20. Suppose line G is parallel to line R, and line E is perpendicular to line G.

Point (-10,8) lies on both line R and line E. The equation for line R is y= ___. The equation for line E is y= ___.
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0
R is y=x equation for line E is y=G
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VXYZ is a kite. What is the length of XY?
olga nikolaevna [1]

Answer:

5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 10  \div2 \\ x = 5 \\ length \: of \: xy = 3 \times 5 + 4 \\  = 15 + 4 \\  = 19

8 0
2 years ago
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Solve a,b,c,d and e.​
Westkost [7]

Answer:

Step-by-step explanation:

a)

 428721

Place of 2's 10s and 10,000s

Therefore its value is 20 and 20,000

Product of the place value = 20 x 20,000 = 4,00,000

b)

37,20,861

Place of 7 is 1,00,000

Therefore the place value is 7,00,000

c)

Greatest 7 digit number is 99,99,999

Adding 1 to it = 99,99,999 + 1 = 1,00,00,000

d)

85642 = 80000 + 5000 + 600 + 40 +2

e)

round off 85642  to nearest thousand = 86,000

7 0
2 years ago
URGENT WILL GIVE BRAINLIEST IF CORRECT!!!!
Snowcat [4.5K]

Answer:

A could represent the volume of a full bottle of the hot sauce.

Step-by-step explanation:

If we say that a full bottle of hot sauce is 100 ml, 90% of that would be 90ml, meaning that <em>x</em> is 90ml.

In this scenario, (10/9)x would equal 100ml, so it has to be the answer.

5 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
2 years ago, father age was nine times the son age but 3 years later it will be 5 times only. find the present ages of the fathe
Goshia [24]

Answer:

<u><em>The Father is currently 47 and the Son is 7</em></u>

Step-by-step explanation:

Let F and S be the present ages of Father and Son, respectively.

We are told that <u>(F-2) = 9(S-2)</u> [2 years ago, father age was nine times the son age]

We also learn that <u>(F+3) = 5(S+3)</u>  [3 years later it will be 5 times only]

Take the first expression and isolate one of the variables (S or F).  I'll isolate F:

(F-2) = 9(S-2)

F = 9S - 16

Now use this in the second expression:

(F+3) = 5(S+3)

((9S-16)+3) = 5(S+3)

9S-13 = 5S+15

4S = 28

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Since F = 9S-16,

F = 9*(7)-16

F = 47

<u><em>Father is 47 and Son is 7</em></u>

CHECK:

Was the father 9 times the age of his son 2 years ago?

Father would have been 45 and son 5.  Yes, 9*5 = 45

In 3 years will he be 5 times older than his son?  Yes, Father would be 50 and son would be 10.  5*(10) = 50

3 0
1 year ago
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