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marshall27 [118]
3 years ago
12

Which shows the correct substitution of the values ab and c from the equation 0 = - 3x ^ 2 - 2x + 6 into the quadrati formula?

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

The answer would look something like this:

\frac{2+-\sqrt{2^{2}-4(-3)(6) }}{2(-3)}

There could also have a simplified version.

I hope this helps.

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Cesar and Jocelyn are planning their trips to three countries next year. There are 7 countries they would like to visit. One tri
tresset_1 [31]

Answer:

They need five weeks to make all their travels.

Step-by-step explanation:

Given that Cesar and Jocelyn are planning their trips to three countries next year.

One trip will be one week long, another two days, and the other two weeks.

In conclusion, they need five weeks to make this travel.

7 0
3 years ago
Help please thank you
Artist 52 [7]

Answer:

uahabsihsb

Step-by-step explanation:

  1. shahabajwnznjsiay
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7 0
2 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
What is the answer 27x^3-1=0
chubhunter [2.5K]
X=cubic root 2/27
Glad to help
6 0
3 years ago
Read 2 more answers
A rectangular garden is 20 feet in length and 15 feet in width. You mom wants to create a pathway that will go diagonally throug
Lesechka [4]

Answer:

i think it is 35

Step-by-step explanation:

add 20 to 15

8 0
2 years ago
Read 2 more answers
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