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3 years ago

Find the general solution of the given differential equation. y'' + 2y' + 5y = 3 sin 2t

Mathematics

1 answer:

atroni [7]3 years ago

8 0

Consider, pls, this option.
Please, change the design according to local requirements.

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Solve the given equation. w − 19 = 47

butalik [34]

Answer:

w=66

Step-by-step explanation:

w-19=47

Hey There!

So what we want to do is get the variable on one side (w) and the constant on the other

so essentially what I am saying is that we have to get rid of the -19 and to do that we have to add 19

but remember whatever we do to one side we have to do to the other

-19+19 cancels out

47+19=66

therefore

w=66

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3 years ago

If f(a)=b and g(b)=c are functions then domain and range of fog and gof equals to

lorasvet [3.4K]

Answer:

fog =gofthen it will be equal

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4 years ago

3. Solve for x. Round to the nearest tenth * 25 16 22

Marrrta [24]

Answer:

51.3 degrees

Step-by-step explanation:

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3 years ago

What’s the correct answer for this?

Yuri [45]

Answer:

Step-by-step explanation:

In the attached file

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4 years ago

You are making 5 Autumn Classic bouquets for your friends. You have $610 to spend and want 24 flowers for each bouquet. Roses co

Sindrei [870]

There are 16 Roses , 2 Tulips , 6 Lilies in each Autumn Classic Bouquet.

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

Elimination Method
Substitution Method
Graph Method

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

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Let For Each Bouguet:

Number of Roses = R

Number of Tulips = T

Number of Lilies = L

$\texttt{ }$

There are 24 flowers for each bouquet.

$R + T + L = 24$ → Equation 1

$\texttt{ }$

You have $610 to spend for 5 bouguets.

Roses cost $6 each, tulips cost $4 each, and lilies cost $3 each.

$6R + 4T + 3L = 610 \div 5$

$6R + 4T + 3L = 122$ → Equation 2

$\texttt{ }$

You want to have twice as many roses as the other 2 flowers combined in each bouquet.

$R = 2 ( T + L )$ → Equation 3

$\texttt{ }$

Equation 1 ↔ Equation 3:

$R + T + L = 24$

$2 ( T + L ) + T + L = 24$

$3T + 3L = 24$

$T + L = 8$

$T = 8 - L$ → Equation 4

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Equation 4 ↔ Equation 3:

$R = 2 ( T + L )$

$R = 2 ( 8 - L + L )$

$R = 2 ( 8 )$

$\boxed{R = 16}$

$\texttt{ }$

Equation 2 ↔ Equation 4:

$6R + 4T + 3L = 122$

$6(16) + 4(8 - L) + 3L = 122$

$96 + 32 - 4L + 3L = 122$

$L = 96 + 32 - 122$

$\boxed{L = 6}$

$\texttt{ }$

Equation 4:

$T = 8 - L$

$T = 8 - 6$

$\boxed{T = 2}$

$\texttt{ }$

<h2>Conclusion:</h2>

There are 16 Roses , 2 Tulips , 6 Lilies in each Autumn Classic Bouquet.

$\texttt{ }$

<h3>Learn more</h3>

Perimeter of Rectangle : brainly.com/question/12826246
Elimination Method : brainly.com/question/11233927
Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

7 0

3 years ago