Estimate this answer to the nearest whole mumber 48.6+22.98+7.83 =

What is the range of the function y = e Superscript 4 x

Alborosie

Answer:

A. Less than zero

Step-by-step explanation:

So If you graph the function, you'll see that it never actually crosses the y axis into the third or fourth quadrant, the quadrants where all y values become negative.

The answer A is also correct on Edge

Have a great day dude

3 0

3 years ago

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A number is greater than 8. The same number is less than 10. The inequalities x > 8 and x < 10 represent the situation.

Semenov [28]

Answer:

There are infinite solutions because there is always another number between any two numbers.

Step-by-step explanation:

Pick any number (including decimal) add an extra decimal after the smallest one and then you have a number between them. E.g.

1.234 and 2.987

1.2341, 1.2342, 1.2343, ... are all between them

7 0

3 years ago

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15 minus the product of 5 times the difference of p minus 6

m_a_m_a [10]

Written just as an expression it would be:

15-5(p-6)

3 0

3 years ago

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Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago

A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50%50% of this population prefer

n200080 [17]

Answer:

0.1527

Step-by-step explanation:

Given that a researcher wishes to conduct a study of the color preferences of new car buyers.

Suppose that 50% of this population prefers the color red

15 buyers are randomly selected

Let X be the no of buyers who prefer red.

X has exactly two outcomes red or non red.

Also each buyer is independent of the other

Hence X is binomial with p = 0.5 and n = 15

Required prob =The probability that exactly three-fifths of the buyers would prefer red

= P(X=9)

= $15C9 (0.9)^9 (0.6)^6$

= $5005(0.0000305)=0.1527$

6 0

3 years ago