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Verdich [7]
3 years ago
11

Part A: Factor 2x2y2 + 6xy2 + 18x2y2. Show your work.

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

A.

2xy^2(10x+3)

B.

(x+5)^2

C.

(x-6)(x+6)

Step-by-step explanation:

Part A. The expression 2x^2y^2+6xy^2+18x^2y^2 consists of three terms: 2x^2y^2,\ \ 6xy^2,\ \ 18x^2y^2 The first and the last terms are like terms, we can add them:

2x^2y^2+18x^2y^2=20x^2y^2

Now,

20x^2y^2=2xy^2\cdot 10x\\ \\6xy^2=2xy^2\cdot 3

So,

2x^2y^2+6xy^2+18x^2y^2=2xy^2(10x+3)

Part B. The expression x^2+10x+25 is a square of x+5, so

x^2+10x+25=(x+5)^2

Part C. Use the difference of squares formula:

x^2-36=x^2-6^2=(x-6)(x+6)

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