Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
Answer:
Can I have the rest of the question?
Step-by-step explanation:
I think it would be two units up and 1 unit to the left.
If you have any more questions, let me know. <3
Answer:
D) f(x) = (1/2)^x
Step-by-step explanation:
at least that is what I think answer D is supposed to be.
I guess the other answer options are actually
A) f(x) = -2^x
B) f(x) = 2^x
C) f(x) = (1/2)^-x
let's look at the most interesting point here : (1, 1/2).
when x=1, then y = 1/2
A fails. because for x = 1 we get y = -2.
B fails. because for x = 1 we get y = 2.
C fails. because for x = 1 we get (1/2)^-1
and that is 1 / 1/2 = 2
so, the only function giving us (1, 1/2) is D, as
(1/2)¹ = 1/2
Answer:
Step-by-step explanation:
(8x^5+ 6x^3 – 2x² + 10x) – (9x^5– x^3– 13x² + 4) =
-x^5+7x^3+11x^2+10x-4
