Answer:
3
Step-by-step explanation:
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
Answer:
Step-by-step explanation:
Step 1: Write out equation
5gA + mA = B³
Step 2: Factor out A
A(5g + m) = B³
Step 3: Divide both sides by 5g + m
1. X = 14
2. X = 120
3. X = 9.24
4. X = 16
5. X = 193.6
6. X = 11
7. X = 7.8
8. X = 446.4
9. X = 26.25
10. X = 6.6
11. X = 9
12. X = 2.01
Answer:
f(x) = (-4/5)*x + 4
Step-by-step explanation:
The line which passes through these points will decrease y by 12 for every x increase of 15. This is the same as decreasing y by 4 for every x increase of 5. This means the slope (rise over run) is -4/5. If this is applied to the first point to find what y is at 0, then the point (0, 4) is on the line.
This means that f(x) = (-4/5)*x + 4
