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Kitty [74]
4 years ago
9

What element is used to configure a new paragraph?

Computers and Technology
1 answer:
Zepler [3.9K]4 years ago
5 0
You skip a line down and then u indent and start a new paragraph(please don't report if wrong)
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The this reference . a) can be used implicitly b) must be used implicitly c) must not be used implicitly d) must not be used 25)
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Answer:

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Explanation:

because computers

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In order to print multiple worksheets, what needs to happen before printing?
ryzh [129]

Answer:

Explanation:

Click the File tab.

Click Print, or press the control p keyboard command.

On the Print screen, select the printer and other settings.

Click Print.

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How does a computer work
ivann1987 [24]

Answer:

computer works on electricity

Explanation:

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Mila [183]

While natural language understanding focuses on computer reading comprehension, natural language generation enables computers to write. NLG is the process of producing a human language text response based on some data input. This text can also be converted into a speech format through text-to-speech services.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

6 0
3 years ago
ask user to input a string. (assume length of input string is 1) If the string is lower case, print its upper case If the string
Helga [31]

Answer:

import java.util.*;

import java.util.Scanner;

class Main

{

public static void main(String[] args) {

System.out.println("Enter String");

Scanner sc1=new Scanner(System.in);

String s1= sc1.nextLine();

boolean b= isNumerc(s1);

if (b== true)

{

    System.out.println("Its number: Sorry");

}

else

{

boolean a=isStringUpperCas(s1);

if(a == false)

{

    System.out.println(s1.toUpperCase());

}

else

{

    System.out.println(s1.toLowerCase());

}

}

}

private static boolean isStringUpperCas(String st1){

     

     

      char[] arr = st1.toCharArray();

     

      int k =0; boolean flag=true;

      while(k<arr.length)

      {

         

          if( Character.isUpperCase( arr[k] ))

          {

              flag=true;

              k++;

          }

          else

          {

              flag=false;

              k++;

          }

         

      }

      return flag;

}

             

  public static boolean isNumerc(final String st1) {

     

      if (st1 == null || st1.length() == 0) {

          return false;

      }

      for (char ch : st1.toCharArray()) {

          if (!Character.isDigit(ch)) {

              return false;

          }

      }

      return true;

  }

 

}

Explanation:

Please find the program above.

8 0
3 years ago
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