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andrey2020 [161]

4 years ago

7

Your manager has asked you to write a program that displays the percentage of males and female in your class. The program should

prompt the user to enter the number of males and females and display the results.

Computers and Technology

1 answer:

Blababa [14]4 years ago

7 0

<u>Explanation:</u>

The program using <em>python programming language </em>would be:

First, we write the Input prompt.

<u>Input prompt for the user</u>

number_of_males_in_class = int (input ('Enter the number of males: '))

number_of_females_in_class = int(input('Enter the number of females: '))

Next, we write the Process algorithm.

<u>Process algorithm</u>

total_number_of_students_in_class = number_of_females_in_class + number_of_males

_in_class

percentage_of_males_in_class = number_of_males_in_class / total_number_of_students

_in_class

percentage_of_females_in_class = number_of_females / total_number_of_students

Finally, the Output process

<u>Output process</u>

print('Total number of males in class =', format(percentage_of_males_in_class, '.0%'))

print('Total number of females =', format(percentage_of_females_in_class, '.0%'))

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

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Answer:

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<em />

Explanation:

Given

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$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

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It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

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$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

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Convert fraction to decimal

$q = 1 - 0.95$

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------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

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$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0

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