Answer:
Step-by-step explanation:
circumference= pi * diameter
diameter= 2 * radius
circumference= pi *2(5)
c= 10pi
Answer is 5 , you substitute the letter n with the term position which in this case is tenth
Mark as brainleast plzzz
Answer:
option D
Step-by-step explanation:
x/-3≤3
multiply by (-1) on both sides
x/3≥-3
x>=-9
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
Let's think of something that one can hold against a page and draw a circle. Some examples are: a cup, a D battery, a can of soda, the tube from the inside of a paper towel roll, a can of beans, etc.
Think of the can of beans. The part that touches the page (and that you trace around with your pencil) is called a face.What these items have in common is that the faces at the ends are circles (they may or may not be the same size).
The name for this 3-D figure is called a cylinder. Her block, therefore, is a cylinder.
Technically, if the ends were ovals we would still call it a cylinder and so to make sure you have the one with the circles at the ends you would say you have a "right circular cylinder" but for most cases people just say "cylinder" and assume the ends are circles. It really depends what level (elementary, middle school, hs, college) of math you are doing whether just cylinder suffices.
