Check the picture below, notice those three quadrilaterals.
the square, is really a rectangle and is also a rhombus, but with right-angles and equal sides.
Do you think than i ve understood it right
3x+9=30
3x=21
x = 21/3 = 7
x = 7
hope helped
It's important that you share the complete question. What is your goal here? Double check to ensure that you have copied the entire problem correctly.
The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
Check the original problem. If it's different from that which you have shared, share the correct version and come back here for further help.
Well, 9 is the largest, but 4 is the smallest and 3 is the second odd number.
So it would go yes, no, no or if it's just one question, it would be no.
Did you just state the answer? Because it seems like you just answered the question for us.
