Answer:
Control limits for x_bar are between 59.076 and 60.924
Control limits for R are between 0.669 and 5.331
Explanation:
Given data:
x_bar = 60 mph
n = 10
R = 3 mph
Step 1: Factors (see table attached)
At n = 10, factors for computing control charts limits are,
A2 = Mean factor = 0.308
D3 = Lower range = 0.223
D4 = Upper range = 1.777
Step 2: Control limits for x_bar
Lower Control limit:
LCL = x_bar - A2*R = 60 - (0.308)(3) = 60 - 0.924 = 59.076
Upper Control limit:
UCL = x-bar + A2*R = 60 + (0.308)(3) = 60 + 0.924 = 60.924
The control limits for x_bar are between 59.076 and 60.924
Step 3: Control limits for R
Lower Control limit:
LCL = D3*R = 0.223(3) = 0.669
Upper Control limit:
UCL = D4*R = 1.777(3) = 5.331
The control limits for R are between 0.669 and 5.331
Hope this helps!
Answer:
$71,000
Explanation:
The computation of operating income is shown below:-
Total costs if company bought = Cost of production × Outside supplier per unit) + (Fixed cost × Remaining percentage)
= (43,000 × $3.80) + ($68,000 × (100% - 30%))
= (43,000 × $3.80) + ($68,000 × 70%)
= $163,400 + $47,600
= $211,000
Loss in Income if part is bought = Total costs if company bought - Total costs originally
= $211,000 - $140,000
= $71,000
Therefore, Making profit will be more by $71,000 and for computing the Loss in Income if part is bought we simply applied the above formula.
Answer:
Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.
Explanation:
activity A =
normal time (NT) = 5 days
Normal cost (NC) = $0
crash time (CT) = 3 days
Crash cost (CC) = $500
crash cost per day = [CC - NC]/[CT - NT] = $250/day
activity B:
normal time (NT) = 6 days
Normal cost (NC) = $0
crash time (CT) = 4 days
Crash cost (CC) = $50
crash cost per day = [CC - NC]/[CT - NT] = $25/day
activity C:
normal time (NT) = 8 days
Normal cost (NC) = $0
crash time (CT) = 3 days
Crash cost (CC) = $1000
crash cost per day = [CC - NC]/[ CT- NT] = $200/day
The activity that takes the least cost to speed up is the first one to be crashed. from the computations, activity B takes the least cost to speed up, so the project manager should crash activity B first by 2 days.
Therefore, Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.
The best and most correct answer among the choices provided by the question is the fourth choice. <span>"Shareholder wealth" in a firm is represented by </span><span>the market price per share of the firm's common stock. </span><span>I hope my answer has come to your help. God bless and have a nice day ahead!</span>
