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Andru [333]
3 years ago
13

A fair die is rolled 10 times. What is the average number of even number outcomes?

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

Answer:

3/6=1/2 so one half

Step-by-step explanation:

3/6 × 10 =30/60=3/6=1/2

Hatshy [7]3 years ago
3 0

Answer:

Average number of even number outcomes =5

Step-by-step explanation:

Probability = number of possible outcome / sample space

A fair die has sides labeled 1,2,3,4,5,6.

Therefore sample space = 6

Odd numbers = 1,3,5

Possible outcome of odd numbers = 3

Even numbers = 2,4,6

Possible outcome of even numbers = 3

Probability of even numbers = possible outcome of even numbers / sample space

Probability of even numbers = 3/6 = 1/2.

If the die is rolled 10times

Total number of outcome = 10

Average number of even number outcomes = probability of even numbers * total number of outcome

= 1/2 x 10

= 5

Average number of even number outcomes =5

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Answer:

The solution is x =0.

Step-by-step explanation:

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Now, taking the inverse sine of both sides we get:

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\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

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4 0
3 years ago
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 140 lb and each bo
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Answer:

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Step-by-step explanation:

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3 years ago
I need help on this pleaseee
Leona [35]

Answer:

QUESTION:

I need help on this pleaseee...

ANSWER:

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Step-by-step explanation:

Hope that this helps you out! :)          

If you have any questions please put them in the comment section below this answer.          

Have a great rest of your day/night!          

Please thank me on my profile if this answer has helped you.

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3 years ago
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3 years ago
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victus00 [196]

Answer:

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