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Flura [38]
3 years ago
15

Round 977.259856871 to 3 decimal places

Mathematics
2 answers:
Fofino [41]3 years ago
5 0
You will want to round to 977.259

look at the number to the right of 9, it is 8, and 8 > 5. IF the number is 5 or greater, round up.

so your answer is 977.260

hope this helps
fgiga [73]3 years ago
3 0
977.259856871
The third decimal place is 9.
The number after that is above 5, so round up.
Your answer should be 977.260
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A line passes through the point (-2,7) and had a slope of -5
Annette [7]

Answer:

a = -1

Step-by-step explanation:

The general equation for a straight line is y = mx+c, where m is the gradient/ slope, so m = -5. The first thing we need to do is find c, which we do by plugging in the x and y values that we already know: y = 7 and x = -2

7 = -5*(-2) + c

7 = 10 + c

c = 7-10 = -3

Now, we have the general equation of y = -5x -3 and we can use this to find a.

We'll treat a as x and y will be equal to 2:

2 = -5a -3

5 = -5a (Divide both sides by 5)

-a = 1 (now by -1)

a = -1

7 0
3 years ago
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Explain how the math drawing can help you solve 8+ =14​
butalik [34]

Answer:

8+6=14

Step-by-step explanation:

that is my answer ig

4 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
2 years ago
How would I solve this agai n
Svetllana [295]

Answer:

The area is 35 inches

Step-by-step explanation:

You will need to cut the shape into 3 parts

the 3 by 3

2 by 5

and 4 by 4

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3 0
2 years ago
Read 2 more answers
The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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