12 15.2 15.7 17 18.1 18.8 21
Answer:
60.00 in^2
Step-by-step explanation:
First focus on the area ABOVE the dotted line. The shape here is that of a trapezoid. The two leg lengths are 12 in and 18 in (18 in is the diameter). At the far right of this trapezoid we can picture a triangle of base 3 in, height h and hypotenuse 5 in. Using the Pythagorean Theorem, we get h = 4 in.
This 4 in measurement is the width of the trapezoid. Thus, we are now ready to apply the formula for the area of a trapezoid: A = (average length of legs)*(width).
Here that area comes out to
12 in + 18 in
A = --------------------- * 4 in = 15 in*4in = 60 in^2, or (to the nearest hundredth)
2 60.00 in^2
Answer:
∠AOC = 50°
B is correct.
Step-by-step explanation:
In the given figure of protractor measure the ∠AOC
Please find the attachment of protractor.
OA is horizontal line which is base of protractor.
In angle AOC, two legs OA and OC
OA is base of protractor. OC another leg.
Now we see position of leg OC of angle AOC.
∠AOC is acute angle. So, see the number bottom of protractor.
Hence, the measure of ∠AOC is 50°
Answer:
308cm^3
Step-by-step explanation:
maths
