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Firdavs [7]
3 years ago
11

Select the correct answer.

Mathematics
2 answers:
ycow [4]3 years ago
7 0
It should be the money spent by a seller to advertise a product
yan [13]3 years ago
6 0

Answer:

the money spent by a buyer to purchase a product

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The perimeter of the square can be represented by the expression 36x+44 robin wants to write an equivalent expression for the pe
sukhopar [10]

Answer:

4  (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

Step-by-step explanation:

Here, given The perimeter of the square  = (36 x+44)

Now,as we know :

PERIMETER OF SQUARE = 4 x ( SIDES)

Simplifying the perimeter expression.

Take 4 common out of the expression (36 x+44), we get:

(36 x+44) =  4 (9 x + 11)

⇒ Perimeter of the square  =  4 x  (9 x + 11)

⇒4 x ( SIDES) = 4 x (9 x + 11)

⇒ Each Side = (9 x + 11)

Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

5 0
3 years ago
if a car travels 370.3 miles on 52 liters of gas, how many liters of.gas.will take to go 722 miles.if the car travels at the sam
blsea [12.9K]

Answer:

101.4 liters.  

Step-by-step explanation:

First of all we will find mileage of car.  

\text{Mileage of car}=\frac{\text{Total distance traveled}}{\text{Total amount of fuel}}

\text{Mileage of car}=\frac{370.3\text{ miles}}{52\text{ liters gas}}

\text{Mileage of car}=7.12115\frac{\text{ miles}}{\text{ liters gas}}

We can see that car travels at the rate of 7.12 miles per liter gas. Now let us find amount of gas needed to travel 722 miles at the same rate.

\text{Amount of gas needed}=\frac{722}{7.12}

\text{Amount of gas needed}=101.388

Therefore, it will take 101.4 liters of gas to travel 722 miles.

4 0
2 years ago
Please help me solve ​
IgorLugansk [536]
Here’s the answer
Enjoy

3 0
3 years ago
Which 2 equations would you use to solve this system?
slega [8]

Answer:

x-y=4

and

x+y=32 is <u>your</u><u> </u><u>equation</u>

<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>

<u>s</u><u>u</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>=</u><u>x</u><u>+</u><u>y</u><u> </u><u>i</u><u>s</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>3</u><u>2</u>

<u>x</u><u>-</u><u>y</u><u>=</u><u>4</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>1</u><u>)</u>

<u>x</u><u>+</u><u>y</u><u>=</u><u>3</u><u>2</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u>

<u>a</u><u>d</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>2</u>

<u>x</u><u>-</u><u>y</u><u> </u><u>+</u><u>x</u><u>+</u><u>y</u><u>=</u><u>4</u><u>+</u><u>3</u><u>2</u>

<u>2</u><u>x</u><u>=</u><u>3</u><u>6</u>

<u>x</u><u>=</u><u>3</u><u>6</u><u>/</u><u>2</u><u>=</u><u>1</u><u>6</u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>1</u>

<u>1</u><u>6</u><u>-</u><u>y</u><u>=</u><u>4</u>

<u>1</u><u>6</u><u>-</u><u>4</u><u>=</u><u>y</u>

<u>y</u><u>=</u><u>1</u><u>2</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

4 0
2 years ago
(4,7,12,19) How do you right this in recursive and explicit equations??????? pls help
Soloha48 [4]

You can see how the difference between two consecutive terms is constantly increasing:

a_1 = 4

a_2 = 7 = 4+3

a_3 = 12 = 7+5

a_4 = 19 = 12+7

So, for the next terms we'll have to add +9, +11, +13 and so on.

Also, note that a_2 is obtained by adding the 2nd odd number to a_1, a_3 is obtained by adding the 3rd odd number to a_2, and so on.

So, the recursive formula is

a_n = a_{n-1}+(2n-1),\quad a_1=1

For the explicit formula, recall that the sum of the first n odd numbers is n squared. Taking into account the fact that we're not starting from 1, we have

a_n = n^2+3

7 0
3 years ago
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