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kondaur [170]
3 years ago
7

URGENT PLEASE HELP x/240 = 82/100 what is X?

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0

x/240 = 82/100

240 : 100 = 2.4

so 240 is divided with 2,4 giving 100, this will work with 82 too. So, 82 × 2.4 = 196,8

Answer : x = 196,8

prove :

196,8/240 = 82/100 = 41/50

see the picture

Tju [1.3M]3 years ago
6 0

Answer:

x= 984/5 or 196 4/5 or 196.8

Step-by-step explanation:

first we reduce the fraction to lowest form

x/240=41/50

then we cross multiply and we get

50x= 9840

x= 9840/50( zero and zero would be canceled with each other )

x= 984/5 or 196 4/5 or 196.8

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write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o
Alenkinab [10]
\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\
f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}
\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see,
 
\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
5 0
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