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Vesna [10]
3 years ago
15

What are the 11 signs of climate change

Biology
1 answer:
77julia77 [94]3 years ago
7 0

Answer:The 11 signs of climate change are:

1. Temperature rises world wide due to green house gases.

2.Droughts becomes longer and extreme.

3.Tropical storm becomes more severe because of warmer ocean temperature.

4.Glaciers melts fast.

5. Sea levels rises.

6.threatens coastal communities.

7.sea ice in North Pole and south poles melts faster because of the warmer temperature.

8.permafrost melts releasing methane.

9.Extreme weather.

10. Impact on animalsale nd plants.

11. Disappearing a ice.

Explanation:

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Help it’s for a test if you don’t know pls don’t guess
ivanzaharov [21]

Answer:

100 percent because all would result Pp and the (p) which is white and recessive allele would express only in absence of dominant allele (P)

6 0
2 years ago
I WILL GIVE U BRAINLEST what has hands but can’t clap
True [87]

Answer:  clock cant clap

Explanation:

5 0
3 years ago
Read 2 more answers
The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
2 years ago
What are all the steps in a descriptive investigation?
I am Lyosha [343]

Explanation:

Make an observation about a phenomenon (qualitative and/or quantitative)

Ask a research question.

Hypothesize a possible answer for your question.

Create a procedure to test your hypothesis.

Identify what you are testing.

Identify your control group/experimental group.

7 0
2 years ago
When are lipids (fat molecules) broken down into smaller molecules by your body?
BaLLatris [955]

Answer: <u>Lipids can also be broken down into their components(hydrolysis). Reason 1, When you eat fats, they are broken down by your digestive system and turned into products that can be used for other functions. Reason 2, When the body has run out of quick energy, and needs to tap into stored energy.</u>

Explanation:

8 0
2 years ago
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