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3 years ago

A student is trying to solve the system of two equations given below:

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

Answer:

(y+z=6)*-3

Step-by-step explanation:

using this would make the top equation or (y+z=6) turn negative and would be this [-3y-3z=-18) using the distributive property. Since the bottom equation has a positive 3y. The -3y from the top equation and 3y from the bottom ones cancel out leaving you with z=-17 when combining like terms.

SpyIntel [72]3 years ago

4 0

Answer:

c is the answer since you are trying to make the ys number (-/+) of the value the other y contains

(3) so you will multiply the first equation by -3 to be able to eliminate y

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Lina20 [59]

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The power set of $Z$ is

$\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}$

1. $\{a,c\}\subseteq Z$ is true because both $a\in Z$ and $c\in Z$ .

2. $a\in Z$ is true.

3. $\{c\}\subseteq Z$ is true (same reason as part 1).

4. $\{c\}\in Z$ is false because $Z$ does not contain the set $\{c\}$ , rather just the element $c$ itself.

5. $b\in Z$ is false because the element $b$ on its own simply is not in $Z$ . That $b\in\{a,b\}$ does not mean $b\in Z$ , but that $b$ belongs to a subset of $Z$ .

6. $\{a,b\}\in Z$ is true.

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3 years ago