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3 years ago

10

A student is trying to solve the system of two equations given below:

2 answers:

marissa [1.9K]3 years ago

6 0

Answer:

(y+z=6)*-3

Step-by-step explanation:

using this would make the top equation or (y+z=6) turn negative and would be this [-3y-3z=-18) using the distributive property. Since the bottom equation has a positive 3y. The -3y from the top equation and 3y from the bottom ones cancel out leaving you with z=-17 when combining like terms.

SpyIntel [72]3 years ago

4 0

Answer:

c is the answer since you are trying to make the ys number (-/+) of the value the other y contains

(3) so you will multiply the first equation by -3 to be able to eliminate y

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Solve for g.<br> g/6 - -53 = 57

Mashcka [7]

Step-by-step explanation:

g/6 - -53 = 57

g/6 + 53 = 57

g/6 = 4

g = 4×6 = 24

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2 years ago

Carlos tried to shade all the factors of 30 on the hundred chart. Hundred chart with 1, 2, 3, 5, 6, 10, 15, and 30 shaded. What

Nastasia [14]

Answer:

30 is the wrong one because it is not a factor of 100

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Step-by-step explanation:

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2 years ago

Please help fast i will give you the most Brainly <br><br><br> what would n = 3(n+7)=48

neonofarm [45]

Answer:

n = 9

Step-by-step explanation:

3(n+7)=48

distribute

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subtract 21 from each side

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5 0

3 years ago

a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be

ElenaW [278]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ Let the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

$\rightarrow$ Now, clearly it is forming a triangle.

So, in triangle ABC,

$\rightarrow$ $\sf{Tan50° \:= \: \frac{BC}{AC}}$

$\rightarrow$ $\sf{1.19 \:= \: \frac{BC}{50}}$

$\rightarrow$ $\sf{1.19 ×50\:= \: BC}$

$\rightarrow$ $\sf{59.5m\:= \: BC}$

$\rightarrow$ Hence, BC = 59.5m

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$\sf{=\: 61.15m}$

Therefore, total height of the tower = $\sf\purple{ 61.15m.}$

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Hope it helps you:)

5 0

2 years ago

Read 2 more answers

Whats the answer for 6b+7-2b=1+5b

Alecsey [184]

$Solution,6b+7-2b=1+5b\quad :\quad b=6$

$Steps:$

$6b+7-2b=1+5b$

$\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b$

$\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7$

$\mathrm{Simplify}, 4b=5b-6$

$\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b$

$\mathrm{Simplify}, -b=-6$

$\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}$

$\mathrm{Simplify}, b=6$

$\mathrm{The\:Correct\:Answer\:is\:b=6}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

3 0

3 years ago

Read 2 more answers