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amid [387]
3 years ago
10

8x100=8x10 to the second power?

Mathematics
2 answers:
Vlada [557]3 years ago
6 0
False. 800 does not equal 6400
Brilliant_brown [7]3 years ago
3 0

I assume you're asking what this expression is to the second power.

(8*100)^2=(8*10)^2

Simplify

8 squared = 64

100 squared = 10000

8 squared = 64

10 squared = 100

Result:

64 + 10000 = 64 + 100

8x100=8x10 is false

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1/2 is the same number as
MrRa [10]

Answer:

.5

Step-by-step explanation:

1 Divided by 2 is .5 or 1/2

3 0
3 years ago
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Solve the following system using the SUBSTITUTION method.<br> x - 3y = 2<br> 2x - 6y = 6
notka56 [123]

ANSWER:

  • x – 3y = 2 ...(1)
  • 2x – 6y = 6 ...(2)

On solving eq(1), we get

  • x – 2 = 3y
  • x – 2/3 = y

Plug the value of x in eq(2)

  • 2x – 6(x - 2/3) = 6
  • 2x – 2(x – 2) = 6
  • 2x – 2x + 4 = 6
  • 0 = 6 – 4
  • 0 ≠ 2

So, given system of equations is not correct.

6 0
3 years ago
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Solve for x what is -2x-4&lt;10
tino4ka555 [31]

the answer is x is greater then -7

to find this add 4 to each side

then divide by -2.

since you divided both sides by a negative the symbol flips and you get x is greater then -7

7 0
3 years ago
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A number w added to 2.3 is more than 18
DanielleElmas [232]
2.3 + w > 18
-2.3 -2.3
w > 15.7
7 0
3 years ago
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
3 years ago
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