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djyliett [7]
3 years ago
15

Is root 1 = 1? I need S or NO...

Mathematics
2 answers:
olganol [36]3 years ago
8 0
Yes. It can be written as -1 or positive 1.
valentina_108 [34]3 years ago
3 0
Yes, but no quiet right, because root 1 is equal to both +1 and -1
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Plz help me answer this
timofeeve [1]

Answer:

(-2, -8)

x = -2

y = -8

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define systems</u>

13x - 6y = 22

x = y + 6

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                              13(y + 6) - 6y = 22
  2. Distribute 13:                                 13y + 78 - 6y = 22
  3. Combine like terms:                      7y + 78 = 22
  4. Isolate <em>y</em> term:                                7y = -56
  5. Isolate <em>y</em>:                                         y = -8

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                    x = y + 6
  2. Substitute in <em>y</em>:                                     x = -8 + 6
  3. Add:                                                      x = -2
4 0
3 years ago
Given x less than y, compare the following expressions and determine which is greater: 2x-y;2y-x. Explain your answer
sweet [91]

Let's form the difference of the two expressions and see what we can learn.

(2y -x) -(2x -y) = 2y -x -2x +y = 3y -3x = 3(y -x)

Since y > x, this is positive, so 2y -x is greater than 2x -y.

8 0
3 years ago
Directions:Simplify the following monomials.SHOW ALL STEPS!
Mandarinka [93]

Answer:

<u>7. Ans</u>;

\frac{6 {a}^{5}  {b}^{7} }{ - 2 {a}^{3} {b}^{7}  }   =  \frac{2 {a}^{3} {b}^{7}(3 {a}^{2} )  }{ - 2 {a}^{3}  {b}^{7} }  =  - 3 {a}^{2}

___o____o___

<u>8. Ans</u>;

\frac{ - 20 {x}^{3}  {y}^{2} }{ - 5 {x}^{3}y }  =  \frac{ - 5 {x}^{3}y(4y) }{ - 5 {x}^{3}y }  = 4y

___o___o___

<u>9. Ans</u>;

\frac{ - 16 a {b}^{4}  }{4 {b}^{3} }  =  \frac{4 {b}^{3}( - 4ab) }{4 {b}^{3} }  =  - 4ab

____o____o____

<u>10. Ans;</u>

\frac{21 {m}^{8}  {n}^{5} }{27 {m}^{5} {n}^{4}  }  =  \frac{3 {m}^{5} {n}^{4}(7 {m}^{3} n)  }{3 {m}^{5} {n}^{4}(9)  }  =  \frac{7 {m}^{3}n }{9}

___o___o___

<u>11. Ans;</u>

\frac{ - 15 {x}^{5}  {y}^{4} }{45x {y}^{3} }  =  \frac{ 15x {y}^{3} ( -  {x}^{4} y)}{15x {y}^{3}(3) }  =  -  \frac{ {x}^{4}y }{3}

___o___o___

<u>12.Ans;</u>

\frac{7 {p}^{2}  {q}^{2} }{14 {p}^{2} {q}^{2}  }  =  \frac{7 {p}^{2} {q}^{2}  }{7 {p}^{2} {q}^{2} (2) }  =  \frac{1}{2}  = 0.5

I hope I helped you^_^

7 0
3 years ago
Read 2 more answers
The line a bus arrives at the bus stop every 25 minutes, and the line b bus arrives every 15 minutes.Both are at the stop right
vova2212 [387]

Answer:

  after 75 minutes

Step-by-step explanation:

The least common multiple (LCM) of 15 and 25 is 75. It can be found a couple of ways:

1. List the factors of each number and find the product of the unique ones:

  15 = 3·5

  25 = 5²

The LCM is 3·5² = 75.

__

2. Find the greatest common divisor (GCD) and divide the product of the numbers by that value. From the above list of factors, we see that 5 is the GCD of 15 and 25. Then the LCM is ...

  15·25/5 = 75

__

Or, you can simply list multiples of each number and see what the smallest number is that is in both lists:

  15, 30, 45, 60, <em>75</em>, 90

  25, 50, <em>75</em>, 100

__

The two buses will appear together again after 75 minutes.

5 0
3 years ago
EL QUE PUEDA AYUDARME SE LO AGRADECERIA MUCHO
Vladimir79 [104]

Answer:

La respuesta es 4

Step-by-step explanation:

La Ramon para esto es porque Como 3x4 son igual a 12 ebtonces por eso la respuesta es 4

8 0
3 years ago
Read 2 more answers
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