All categories

3 years ago

What is 6% of 13,530

1 answer:

8 0

To find a specific percent of the number, first find the smallest scale division of the designated percent, or 1%. To find 1% of 13,530, divide it by 100, which yields 135.30. Then, multiply this 135.30 by 6 to find 6%. This comes out to 811.8.

Hope this helps.

You might be interested in

Pls help ASAP i don’t have time!!!!!

Lesechka [4]

Answer:

Step-by-step explanation:

Let the width be W.

14w=(8*10)

14w=80

The width of the frame needs to be at least 5.7 inches.

6 0

3 years ago

What are the answers for 2, 3 , and 4? That’s it

PIT_PIT [208]

Answer:

1. Formula: b * h ÷ 2

12 * 3 = 36 ÷ 2 = 18 in^2

2. Formula: b * h ÷ 2

5 * 8 = 40 ÷ 2 = 20 ft^2

I could only help on two. Hope it helps though! =)

5 0

2 years ago

Jason wrote 1 1/3 as a sum of 3 fractions. None of the fractions had a denominator of 3. What fractions might Jason have used?

ziro4ka [17]

11/6 , 1/6 and 10/6 are the answer

5 0

2 years ago

Grade 8 Math

zavuch27 [327]

Question #1 = <span>the amount of snow that falls each hour
question #2 = the starting amount of snow
algebra sucks, keep up the good work

</span>

5 0

3 years ago

Read 2 more answers

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

2 years ago