The radius is 6
Complete the square on the equation and get
(x-6)^2 + (y-6)^2 =36
The circle equation is
(x-h)^2 + (y-k)^2 = r^2
Center(h,k) r=radius
Hey there! :)
Answer:
First option: As x⇒ ∞ f(x) ⇒ -∞. As x⇒ -∞ f(x) ⇒ ∞.
Step-by-step explanation:
Rearrange the equation:
f(x) = -x³ - 2x² + 1
This is a negative cubic function. The function decreases over the interval
(-∞, ∞). Therefore:
As x⇒ ∞ f(x) ⇒ -∞.
As x⇒ -∞ f(x) ⇒ ∞.
This is the first option.
Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Find coordinate of points
Point P coordinates are (x,y) =
x is same that point L, y = 0 .
Then coordinates for P = (a,0)
Point M coordinates
x is same that point N, x=b
y is same that point L , y=c
Then coordinates for M = (b,c)
