Part 1:the answer is 1/36
each time we roll the dice, the whole probabilities are 6
if we roll it two times
6*6=36
part 2
it's 1/8
each time we flip a coin, the whole probabilities are 2
if we flip it 3 times
2*2*2=8
good luck
Answer: 5,760
Step-by-step explanation:
It was given that each dog is distinct from other dogs and each cat is distinct from other cats, Also from the hint given, the First position is for the dogs. Let D represent the dogs and C represent the Cat , then we have
D C D C D C D C D D or
D D C D C D C D C D or
D C DD C D C D C D or
D C D C D D C D C D or
D C D C D C DD C D
Each of the arrangements above could be done in
2 x 4! x 4! ( it is constant that D is starting , so I am only left with the arrangement of the remaining 5 D's , out of the remaining 5 D's it is also constant that tow of them will be together and this could be done in 2 ways, so I have 4! left for the D's and 4! also for the C's )
= 2 x 24 x 24
= 1 , 152
The total arrangement = 5 x 1 , 152
= 5,7 60 ways
Answer:
Present age
Son: 15
Father: 45
Step-by-step explanation:
Remark
Thank you for the translation. Without it, the problem would be impossible -- at least for me.
Givens
Let the present age of the father = x
Let the present age of the son = y
Solution
x + y = 60
How many years will pass? You could say it's z.
x + z = y When z years pass, the son will be his father's present age.
x + z + y + z = 120 when z is added to both their current ages, the result is 120 Collect like terms
x + y + 2z = 120
<u>x + y = 60 </u> Subtract The very first equation
2z = 60 Divide by 2
z = 60/2 30 years have passed.
z = 30
x + z = y
x + 30 = y Substitute x + 30 for the present y value (the father).
x + x + 30 = 60
2x = 30
x = 15
x + y = 60
15 + y = 60
y = 60 - 15
y = 45
So the son's age right now is 15
The father's age right now is 45
Answer: 454
<u>Step-by-step explanation:</u>
The first three digits will be the significant digits. Round the third digit.
454.12
the digit and the 4 is 1 so 454.12 is rounded to 454
