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Dima020 [189]
4 years ago
10

How would solve 2y+6x=0

Mathematics
1 answer:
Slav-nsk [51]4 years ago
4 0

2y+6x=0

-6x from both sides

2y=-6x+0

then divide by 2 to each side so it looks like this 2y/2=-6x+0/2

the 2 cancels 2y so you're left with y

Then divide -6/2=-3 and 0/2=0

y=-3x+0  

Does that answer your question?

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Find the number of distinct triangles with the measurements a = 5, b =2, and a = 51 degrees.
elixir [45]
The answer is the option b. 1.

Two sides and one angle determine one unique triangle.

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When that is the case you use the cosine rule.

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Simplify. Remove all perfect squares from inside the square root. 12 = 12 ​
Elena L [17]

Answer:

Removing the perfect square 4 in 12 we get 2√3

Step-by-step explanation:

The square root of 12 is

√12 = √(4 x 3)

√12  = 2√3.

There's no special trick here, but it's usually easy to check whether a small number is divisible by 4. Keep this in mind when looking for factors.

Removing the perfect square 4 in  the square root of 12 we get 2√3.

Here 4 is a perfect square it can be written as

√4 =√2^2

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4 0
3 years ago
(a) A company that makes plastic utensils is looking at how the price it charges for a knife affects the number of knives it sel
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8 0
3 years ago
(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)
klemol [59]

Answer:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

Remove parentheses:  (a)=a

=-t^4-5t^3-10t^2+9t^3+3t^2-1

Group like terms

=-t^4-5t^3+9t^3-10t^2+3t^2-1

Add similar elements        

=-t^4-5t^3+9t^3-7t^2-1         ∵ -10t^2+3t^2=-7t^2

Add similar elements        

=-t^4+4t^3-7t^2-1                  ∵  -5t^3+9t^3=4t^3

Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

4 0
3 years ago
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