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4 years ago

I need help with this question please help

Mathematics

1 answer:

forsale [732]4 years ago

4 0

Answer:

Step-by-step explanation:

The formula of a surface area of a cylinder:

$S.A.=2\pi r^2+2\pi rH$

r - radius

H - height

We have:

r = 5 in

H = 4 in

Substitute:

$S.A.=2\pi(5^2)+2\pi(5)(4)=2\pi(25)+2\pi(20)\\\\=50\pi+40\pi=90\pi\ in^2$

$\pi\approx\dfrac{22}{7}$

Substitute:

$S.A.\approx90\cdot\dfrac{22}{7}=\dfrac{1980}{7}\approx282.857\ in^2$

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Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter

Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = $x$ coins

So we can have two inequalities.

1) Total number of coins

$x+17\geq28\\$ [Since minimum number of coins=28]

2) Total value of coins

$10x+(25)(17)\leq505$ [As 1 dime=10 cents and 1 quarter=25 cents]

$10x+425\leq505$

Solving inequality (1)

Subtracting both sides by 17.

$x+17-17\geq28-17$

∴ $x\geq 11$

Solving inequality (2)

Subtracting both sides by 425.

$10x+425-425\leq505-425$

$10x\leq 80$

Dividing both sides by 10.

$\frac{10x}{10}\leq \frac{80}{10}$

∴ $x\leq 8$

On combining both solutions

$x\geq 11$ and $x\leq 8$ ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

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3 years ago

What does being able to express numbers in equivalent forms allows you to do?

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Step-by-step explanation:

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