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Scrat [10]
2 years ago
13

Classify the triangle by its sides and angles

Mathematics
1 answer:
lord [1]2 years ago
8 0

Answer:

Obtuse Scalene Triangle

Give me Brainliest if I'm correct , please ! :)

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A right cone has an altitude of 4 units and a base diameter of 6 units. What is it’s lateral area?
fenix001 [56]

Answer:

Lateral area  =

pi *  (radius) * √ [ height ^2  + radius^2 ]  =

pi *  ( 4 )  * √ [  4^2 + 3^2 ]  =

pi * ( 4 ) * √25  =

pi * ( 4 ) * (5 )  =

20 pi  units^2  ≈   62.8 units^2

Step-by-step explanation:

4 0
3 years ago
8) What is the area of parallelogram RSTU? *
Hatshy [7]
The answer is A. L*W which 4 by 6
7 0
2 years ago
Read 2 more answers
Complete the sentence.
Over [174]

Answer:


Step-by-step explanation:

The horizontal asymtote is when there are no solutions for x, so it is when y = -10.

This is because when y = -10, 0.8^x must be 0, but this is impossible. You can test this by trying 4^x/5^x. It will get super small, but never 0.

5 0
3 years ago
Jia rode her bike 7 7/8 miles in the morning and another 6 5/8 miles in the afternoon. How many miles did she ride altogether
loris [4]

Answer:

14 1/2

Step-by-step explanation:

Rewriting our equation with parts separated

=7 + 7/8 + 6 + 5/8

Solving the whole number parts

7 + 6=13

Solving the fraction parts

7/8 + 5/8= 12/8

Reducing the fraction part, 12/8,

12/8=3/2

Simplifying the fraction part, 3/2,

3/2=1 1/2

Combining the whole and fraction parts

13 + 1 + 12=14 1/2

5 0
2 years ago
Calculus AB
wariber [46]
Assuming you mean
\lim_{x \to 4} \frac{\sqrt{x+5}-3}{4-x}

that means as x approaches 4

if we sub 0 for x we get
0/0
and intermitent form
use l'hopital's rule

so
take the derivitive of the top and bottom seperatly
l'hopitals rule is something like
if \lim_{x \to n} \frac{f(x)}{g(x)} results in 0/0 or -∞/∞ or∞/∞ then keep doing it until f(n)/g(n) gives a form that isn't intermitent

so

take derivitive of top and bottom
\dfrac{\frac{1}{2\sqrt{x+5}}}{-1}
now, if we subsitute 4 for x we get
\dfrac{\frac{1}{2\sqrt{4+5}}}{-1}=

\dfrac{\frac{1}{2\sqrt{9}}}{-1}=

\dfrac{\frac{1}{2(3)}}{-1}=

\dfrac{\frac{1}{6}}{-1}=

\dfrac{1}{-6}=\dfrac{-1}{6}
8 0
2 years ago
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