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Minchanka [31]
3 years ago
7

8.3+3.4y-0.5(12y-3)=

Mathematics
1 answer:
natulia [17]3 years ago
8 0

Answer:

Let's simplify step-by-step.

8.3+3.4y−0.5(12y−3)

Distribute:

=8.3+3.4y+(−0.5)(12y)+(−0.5)(−3)

=8.3+3.4y+−6y+1.5

Combine Like Terms:

=8.3+3.4y+−6y+1.5

=(3.4y+−6y)+(8.3+1.5)

=−2.6y+9.8

Answer:

=−2.6y+9.8

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If you change this expression to a fraction, 7.25 will be : 20/7.25.
Amanda [17]

Answer: D The denominator

Step-by-step explanation: The denominator is always the bottom of your fraction.

3 0
3 years ago
Simplify the following expression 4x + 3t - 2x- 4
allochka39001 [22]

Answer:

2x + 3t - 4

Step-by-step explanation:

Hi,

To simplify the expression, we must combine like terms. To start, let's combine all of the x-values.

4x + 3t - 2x - 4

When we combine 4x and -2x we get 2x.

2x + 3t - 4

We can't combine anything else. They don't have the same variables and 4 doesn't even have a variable, so 2x + 3t -4 is the simplified expression.

I hope this helps :)

4 0
3 years ago
What is the standard form of the number six hundred ninety-five and four hundred thirty-seven thousandths?
trapecia [35]

Answer:

695.437 is your answer :)

6 0
3 years ago
Read 2 more answers
As a butcher, you sell beef in 3.5-pound packages. You anticipate needing 25 packages for the next two days. The
bekas [8.4K]

Answer:

O weight in kilograms = 25 x 3.5 ÷ 2.2

Step-by-step explanation:

As a butcher, you sell beef in 3.5-pound packages. You anticipate needing 25 packages for the next two days.

Therefore, the total number of pounds for the 25 packages =

3.5 pound packages × 25

= 87.5 pounds

We are told that : The wholesaler from whom you purchase large pieces of meat measures the weight of the beef in kilograms.

Note that:

2.2 pounds = 1 kg

Hence:

87.5 pounds =

= 87.5÷ 2.2

= 39.772727273 kg

He needs to buy 39.772727273kg from the wholesaler

The equation can you use to determine the weight of the beef, in kilograms, that you need to purchase from the wholesaler is:

O weight in kilograms = (25 x 3.5) ÷ 2.2

7 0
3 years ago
Please help me to solve this . Thank you so much .
worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0
3 years ago
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